這是編寫多路決策最通用的方法。
請參閱下面給出的語法-
if (condition1) stmt1; else if (condition2) stmt2; - - - - - - - - - - else if (condition n) stmtn; else stmt x;
START Step 1: Declare int variables. Step 2: Read a,b,c,d values at runtime Step 3: i. if(a>b && a>c && a>d) Print a is largest ii.else if(b>c && b>a && b>d) Print b is largest iii. else if(c>d && c>a && c>b) Print c is largest iv. else print d is largest STOP範例以下是執行Else If Ladder條件運算子的C程式− 即時示範
#include<stdio.h> void main (){ int a,b,c,d; printf("Enter the values of a,b,c,d: "); scanf("%d%d%d%d",&a,&b,&c,&d); if(a>b && a>c && a>d){ printf("%d is the largest",a); }else if(b>c && b>a && b>d){ printf("%d is the largest",b); }else if(c>d && c>a && c>b){ printf("%d is the largest",c); }else{ printf("%d is the largest",d); } }輸出您將看到以下輸出−
Run 1:Enter the values of a,b,c,d: 2 4 6 8 8 is the largest Run 2: Enter the values of a,b,c,d: 23 12 56 23 56 is the largest考慮另一個C 程序,它使用else ifladder 顯示學生的成績- 即時示範
#include<stdio.h> int main(){ int marks; printf("Enter the marks of a student:</p><p>"); scanf("%d",&marks); if(marks <=100 && marks >= 90) printf("Grade=A"); else if(marks < 90 && marks>= 80) printf("Grade=B"); else if(marks < 80 && marks >= 70) printf("Grade=C"); else if(marks < 70 && marks >= 60) printf("Grade=D"); else if(marks < 60 && marks > 50) printf("Grade=E"); else if(marks == 50) printf("Grade=F"); else if(marks < 50 && marks >= 0) printf("Fail"); else printf("Enter a valid score between 0 and 100"); return 0; }輸出您將看到以下輸出−
Run 1: Enter the marks of a student:78 Grade=C Run 2: Enter the marks of a student:98 Grade=A#
以上是在C語言中解釋else-if梯形語句的詳細內容。更多資訊請關注PHP中文網其他相關文章!