參考下面的演算法,編寫C程式以顯示X形狀的數字。
Step 1: Start Step 2: Declare variables Step 3: Read number of rows Step 4: for loop satisfies<ul class="list"><li>if(i==j || i+j==rows-1)<ul class="list"><li>print i+1</li></ul></li><li>Print " "</li></ul>Step 5: Print new line Step 6: Stop
The logic to print numbers in X pattern is as follows −
for(i=0;i<rows;i++){ for(j=0;j<rows;j++){ if(i==j || i+j==rows-1){ printf("%d",i+1); }else{ printf(" "); } } printf("</p><p>"); }
Following is the C program to display the numbers in X pattern −
#include<stdio.h> main(){ int i,j,rows; printf("Enter number of rows:</p><p>"); scanf("%d",&rows); for(i=0;i<rows;i++){ for(j=0;j<rows;j++){ if(i==j || i+j==rows-1){ printf("%d",i+1); }else{ printf(" "); } } printf("</p><p>"); } }
當上述程式被執行時,它產生以下結果−
Enter number of rows:10 1 1 2 2 3 3 4 4 55 66 7 7 8 8 9 9 10 10
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