在這個問題中,我們被給定一個學生的記錄,其中包含學生的學號、姓名和百分比。我們的任務是建立一個C程序,將學生記錄儲存為結構,並按照姓名對它們進行排序。
讓我們舉一個例子來理解這個問題,
#輸入 - 學生記錄=
{{ student_id = 1, student_name = nupur, student_percentage = 98}, { student_id = 2, student_name = Akash, student_percentage = 75}, { student_id = 3, student_name = Yash, student_percentage = 62}, { student_id = 4, student_name = Jyoti, student_percentage = 87}, { student_id = 5, student_name = Ramlal, student_percentage = 80}}
輸出 − 學生記錄=
{{ student_id = 2, student_name = Akash, student_percentage = 75}, { student_id = 4, student_name = Jyoti, student_percentage = 87}, { student_id = 1, student_name = nupur, student_percentage = 98}, { student_id = 5, student_name = Ramlal, student_percentage = 80}, { student_id = 3, student_name = Yash, student_percentage = 62}}
為了解決這個問題,我們首先會建立一個儲存學生詳細資料的結構。現在,我們將使用qsort()函數,並在該函數中定義一個比較器函數,該函數將使用strcmp()方法比較結構的名稱。
將學生記錄儲存為結構並按名稱排序的程式
線上示範
//C program to store Student records as Structures and Sort them by Name #include <stdio.h> #include <stdlib.h> #include <string.h> struct Student { int student_id; char* student_name; int student_percentage; }; int comparator(const void* s1, const void* s2){ return strcmp(((struct Student*)s1)->student_name,((struct Student*)s2)->student_name); } int main() { int n = 5; struct Student arr[n]; //student 1 arr[0].student_id = 1; arr[0].student_name = "Nupur"; arr[0].student_percentage = 98; //student 2 arr[1].student_id = 2; arr[1].student_name = "Akash"; arr[1].student_percentage = 75; //student 3 arr[2].student_id = 3; arr[2].student_name = "Yash"; arr[2].student_percentage = 62; //student 4 arr[3].student_id = 4; arr[3].student_name = "Jyoti"; arr[3].student_percentage = 87; //student 5 arr[4].student_id = 5; arr[4].student_name = "Ramlal"; arr[4].student_percentage = 80; printf("Unsorted Student Record:</p><p>"); for (int i = 0; i < n; i++) { printf("Id = %d, Name = %s, Age = %d </p><p>", arr[i].student_id, arr[i].student_name, arr[i].student_percentage); } qsort(arr, n, sizeof(struct Student), comparator); printf("</p><p></p><p>Student Records sorted by Name:</p><p>"); for (int i = 0; i < n; i++) { printf("Id = %d, Name = %s, Age = %d </p><p>", arr[i].student_id, arr[i].student_name, arr[i].student_percentage); } return 0; }
Unsorted Student Record: Id = 1, Name = Nupur, Age = 98 Id = 2, Name = Akash, Age = 75 Id = 3, Name = Yash, Age = 62 Id = 4, Name = Jyoti, Age = 87 Id = 5, Name = Ramlal, Age = 80 Student Records sorted by Name: Id = 2, Name = Akash, Age = 75 Id = 4, Name = Jyoti, Age = 87 Id = 1, Name = Nupur, Age = 98 Id = 5, Name = Ramlal, Age = 80 Id = 3, Name = Yash, Age = 62
以上是C程式以結構體儲存學生記錄,並依姓名進行排序的詳細內容。更多資訊請關注PHP中文網其他相關文章!