在C語言中寫一個程序，印出N個五角數的序列

程式說明

五維體數是帕斯卡三角形的任一行中第五個數字，從左到右或從右到左開始，起始於5項行1 4 6 4 1。

這種數字的前幾個是

1, 5, 15, 35, 70, 126, 210, 330, 495, 715, 1001, 1365

Pentatope numbers belong in the class of figurate numbers, which can be represented as regular, discrete geometric patterns. The formula for the nth pentatopic number is

$$\left(\begin{array}{c}n 3\ 4\end{array}\right)=\left(\frac{n(n 1) ( n 2) (n 3)}{24}\right)=\left(\frac{n^2}{4!}\right)$$

Algorithm

Accept the Nth Term from the User to find the Pentotope Numbers.

Use the formula

$$\left(\begin{array}{c}n 3\ 4\end{array}\right) =\left(\frac{n(n 1) (n 2) (n 3)}{24}\right)=\left(\frac{n^2}{4!}\right)$$

Example

/* Program to print pentatope numbers upto Nth term */
#include<stdio.h>
int main() {
   int n, n1, nthterm, nthterm1, i;
   clrscr();
   printf("</p><p> Please enter the nth term to print Pentatope: ");
   scanf("%d",&n);
   nthterm = n * (n + 1) * (n + 2) * (n + 3) / 24;
   printf("The Pentotpe Number is: ");
   printf("%d", nthterm);
   printf("</p><p></p><p>");
   printf("Printing the Pentotope Numbers upto Nth Term");
   printf("</p><p> Print Pentatope Numbers till the term: ");
   scanf("%d",&n1);
   printf("</p><p></p><p>");
   printf("The Pentotope Numbers are:");
   printf("</p><p></p><p>");
   for (i = 1; i <= n1; i++){
      nthterm1 = (i * (i + 1) * (i + 2) * (i + 3) / 24);
      printf("%d\t", nthterm1);
   }
   getch();
   return 0;
}

輸出

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