深入extjs与php参数交互的详解_PHP
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- WBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWB原創
- 2016-06-01 12:05:47825瀏覽
复制代码 代码如下:
HelloWorld
复制代码 代码如下:
$userName = $_POST["userName"];
$password = $_POST["password"];
$msg = "";
if($userName=="lowkey" && $password=="zq19890319") {
$msg = "登陆成功";
} else {
$msg = "登陆失败";
}
echo($msg);
?>
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