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MySQL多表查詢案例分析

WBOY
WBOY轉載
2023-05-27 10:52:061541瀏覽

多表格查詢

案列說明

笛卡爾積的理解

select id,department_name
from employees,departments;#错的

select id,department_id,department_name
from employees CROSS JOIN departments;#错的

每個員工和每個部門都符合了一遍(查出的條目數= id數*department數)

錯誤原因:缺少連接條件

笛卡爾積的解決

編寫連接條件: 表1.列= 表二.列(若多個表連接,至少要用n-1個連接條件)

select id,employees.name,department_name 
from employees,departments
WHERE employees.name = departments.name;

註:如果要顯示的列在要查詢的表中名字一樣,則要表明,是出自哪個表, eg: employees .name

建議在多表查詢時,標明顯示的是哪個表的資訊(優化)

優化:可以在FROM後使用表的別名,但是一旦使用別名,後續就一定要都用別名

多表查詢的分類

等值連接和非等值連接

  • 等值連接:上述的帶有=的

  • 非等值連接:沒有=的

select t1.id,t1.name,t2.grade
from employees t1,departments t2
WHERE ti.salary BETWEEN t2.lowest_salary AND t2.highest_salary ;#非等值

自連接和非自連接

  • 非自連結:表1和表2連接

  • 自連結:表1和自己連接

#显示员工(t1)和其管理者(t2)的基本信息
select t1.id,t1.name,t2.id,t2.name
from employees t1,employees t2#一个表看作两个表
WHERE t1.manage_id = t2.id ;#自连接

內連接和外連接

  • 內連接:合併含有相同列的表,結果不包含一個表與另一個表不符打的行

  • 外連接:合併含有同一列的表,結果除了內連接的結果還查詢不匹配的行

外連接的分類:左外連接(左表多,補右邊),右外連線(右表多,補左邊),滿外連線

SQL92:使用()建立連線

內連線:見上

#外連線:左表有資料不匹配,在右表加( );反之,在左表加( ),但是MySQL不支援

WHERE t1.department_id = t2.department_id(+)#左连接

SQL99:使用JOIN...ON的方式

內連接

select t1.id,t1.name,t2.department_name,t3.environment
from employees t1 JOIN departments t2
ON t1.department_id = t2.department_id
JOIN locations t3#加入第二个人表
ON t2.department_location = t3.department_location;

外連接

使用OUTER JOIN...ON...

  • #左外連接:LEFT OUTER JOIN

  • 右外連線:RIGHT OUTER JOIN

  • 滿外連線:FULL OUTER JOIN(MySQL不支援)

select t1.name,t2.department_name#左外连接
from employees t1 LEFT OUTER(可省略) JOIN departments t2
ON t1.department_id = t2.department_id;

UMION的使用

合併查詢結果

SELECT colum... FROM table1
UNION (ALL)
SELECT colum... FROM table2
  • UNION運算子

兩個查詢結果的並集,去重(效率低)

  • UNION ALL運算子(建議)

#兩個查詢結果的並集,不去重(效率高)

7種SQL JOINS的實作

MySQL多表查詢案例分析

中圖(內連接):

select t1.name,t2.department_name
from employees t1 JOIN departments t2
ON t1.department_id = t2.department_id;

左上圖(左外連接):

select t1.name,t2.department_name
from employees t1 LEFT JOIN departments t2
ON t1.department_id = t2.department_id;

右上圖(右外連接):

select t1.name,t2.department_name
from employees t1 RIGHT JOIN departments t2
ON t1.department_id = t2.department_id;

左中圖:

select t1.name,t2.department_name
from employees t1 LEFT JOIN departments t2
ON t1.department_id = t2.department_id
WHERE t2.department_id IS NULL;

右中圖:

select t1.name,t2.department_name
from employees t1 RIGHT JOIN departments t2
ON t1.department_id = t2.department_id
WHERE t1.department_id IS NULL;

左下圖(滿外連接) :

#方式一:左上图 UNION ALL 右中图
select t1.name,t2.department_name
from employees t1 LEFT JOIN departments t2
ON t1.department_id = t2.department_id
UNION ALL 
select t1.name,t2.department_name
from employees t1 RIGHT JOIN departments t2
ON t1.department_id = t2.department_id
WHERE t1.department_id IS NULL;

#方式二:左中图 UNION ALL 右上图
select t1.name,t2.department_name
from employees t1 LEFT JOIN departments t2
ON t1.department_id = t2.department_id
WHERE t2.department_id IS NULL
UNION ALL
select t1.name,t2.department_name
from employees t1 RIGHT JOIN departments t2
ON t1.department_id = t2.department_id;

右下圖:

#左中图 UNION ALL 右中图
select t1.name,t2.department_name
from employees t1 LEFT JOIN departments t2
ON t1.department_id = t2.department_id
WHERE t2.department_id IS NULL
UNION ALL
select t1.name,t2.department_name
from employees t1 RIGHT JOIN departments t2
ON t1.department_id = t2.department_id
WHERE t1.department_id IS NULL;

SQL語法新功能

自然連接

使用關鍵字:NATURAL JOIN(不靈活),自動查詢表中所有相同字段,然後進行等值連接

USING連接(不適用於自連接)

#使用關鍵字:USING(同名字段),將表中相同名字的字段自動等值連接

select t1.name,t2.department_name
from employees t1 JOIN departments t2
ON t1.department_id = t2.department_id;
等价于
select t1.name,t2.department_name
from employees t1 JOIN departments t2
USING(department_id);

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