首頁 >後端開發 >php教程 >php比较相似字符串的方法_PHP

php比较相似字符串的方法_PHP

WBOY
WBOY原創
2016-05-30 08:45:19846瀏覽

本文实例讲述了php比较相似字符串的方法。分享给大家供大家参考。具体分析如下:

这里通过php的similar_text函数比较两个字符串的相似性。

$word2compare = "stupid";
$words = array(
  'stupid',
  'stu and pid',
  'hello',
  'foobar',
  'stpid',
  'upid',
  'stuuupid',
  'sstuuupiiid',
);
while(list($id, $str) = each($words)){
  similar_text($str, $word2compare, $percent);
  print "Comparing '$word2compare' with '$str': ";
  print round($percent) . "%\n";
}
/*
Results:
Comparing 'stupid' with 'stupid': 100%
Comparing 'stupid' with 'stu and pid': 71%
Comparing 'stupid' with 'hello': 0%
Comparing 'stupid' with 'foobar': 0%
Comparing 'stupid' with 'stpid': 91%
Comparing 'stupid' with 'upid': 80%
Comparing 'stupid' with 'stuuupid': 86%
Comparing 'stupid' with 'sstuuupiiid': 71%
*/

希望本文所述对大家的php程序设计有所帮助。

陳述:
本文內容由網友自願投稿,版權歸原作者所有。本站不承擔相應的法律責任。如發現涉嫌抄襲或侵權的內容,請聯絡admin@php.cn