首頁  >  文章  >  php框架  >  yii框架怎麼條件查詢

yii框架怎麼條件查詢

爱喝马黛茶的安东尼
爱喝马黛茶的安东尼原創
2019-12-07 15:33:152597瀏覽

yii框架怎麼條件查詢

條件查詢

$customers = Customer::find()->where($cond)->all();

$cond就是我們所謂的條件,條件的寫法也根據查詢資料的不同存在差異,那麼如何用yii2的方式來寫查詢條件呢?

[[簡單條件]]

// SQL: (type = 1) AND (status = 2).  
$cond = ['type' => 1, 'status' => 2]   
// SQL:(id IN (1, 2, 3)) AND (status = 2)  
$cond = ['id' => [1, 2, 3], 'status' => 2]   
//SQL:status IS NULL  
$cond = ['status' => null]

【and】:將不同的條件組合在一起,用法舉例:

//SQL:`id=1 AND id=2`  
$cond = ['and', 'id=1', 'id=2']  
//SQL:`type=1 AND (id=1 OR id=2)`  
$cond = ['and', 'type=1', ['or', 'id=1', 'id=2']]  
//SQL:`type=1 AND (id=1 OR id=2)` //此写法'='可以换成其他操作符,例:in like != >=等  
$cond = [  
    'and',  
    ['=', 'type', 1],  
    [  
        'or',  
        ['=', 'id', '1'],  
        ['=', 'id', '2'],  
    ]  
]

[[or]]:

/SQL:`(type IN (7, 8, 9) OR (id IN (1, 2, 3)))`  
$cond = ['or', ['type' => [7, 8, 9]], ['id' => [1, 2, 3]]

[[not]]:

//SQL:`NOT (attribute IS NULL)`  
$cond = ['not', ['attribute' => null]]

[[between]]: not between 用法相同

//SQL:`id BETWEEN 1 AND 10`  
$cond = ['between', 'id', 1, 10]

[[in]]: not in 用法類似

//SQL:`id IN (1, 2, 3)`  
$cond = ['in', 'id', [1, 2, 3]] or $cond = ['id'=>[1, 2, 3]]
//IN条件也适用于多字段  
$cond = ['in', ['id', 'name'], [['id' => 1, 'name' => 'foo'], ['id' => 2, 'name' => 'bar']]]  
//也适用于内嵌sql语句  
$cond = ['in', 'user_id', (new Query())->select('id')->from('users')->where(['active' => 1])]

##[[like]]:

//SQL:`name LIKE '%tester%'`
$cond = ['like', 'name', 'tester']
//SQL:`name LIKE '%test%' AND name LIKE '%sample%'`
$cond = ['like', 'name', ['test', 'sample']]
//SQL:`name LIKE '%tester'`
$cond = ['like', 'name', '%tester', false]

[[exists]]: not exists用法類似

//SQL:EXISTS (SELECT "id" FROM "users" WHERE "active"=1)
$cond = ['exists', (new Query())->select('id')->from('users')->where(['active' => 1])]

此外,您可以指定任意運算子如下:

//SQL:`id >= 10`
$cond = ['>=', 'id', 10] 
//SQL:`id != 10`
$cond = ['!=', 'id', 10]

PHP中文網,有大量免費的

Yii入門教學,歡迎大家學習!

以上是yii框架怎麼條件查詢的詳細內容。更多資訊請關注PHP中文網其他相關文章!

陳述:
本文內容由網友自願投稿,版權歸原作者所有。本站不承擔相應的法律責任。如發現涉嫌抄襲或侵權的內容,請聯絡admin@php.cn