這篇文章帶給大家的內容是關於java如何使用FromData實作檔案上傳(附程式碼),有一定的參考價值,有需要的朋友可以參考一下,希望對你有幫助。
一、使用FromData將表單物件序列化後,使用request.getInputStream()來取得資料
1、表單程式碼如下
<form id="user-info" method="post" action="upload" > <input type="file" name="file" multiple> <input type="text" name="username"> <input type="text" name="password"> </form> <button id="sub">提交</button>
2、js的程式碼
<script> function createXHR(){ return new XMLHttpRequest(); } var sub = document.getElementById("sub"); sub.onclick=function(){ var xhr = createXHR(); var form = document.getElementById("user-info");//获取上边的表单 xhr.open("post","upload",true); xhr.send(new FormData(form)); } </script>
3、由於是序列化的表單所以java後端,不能使用request. getParameter()取得數據,需要使用request.getInputStream();取得資料
首先我們看到取得的資料
InputStream in = request.getInputStream(); BufferedReader br = new BufferedReader(new InputStreamReader(in)); String str = ""; while((str=br.readLine())!=null){ System.out.println(str); }
可以看到讀取到這些資料
4、接著使用apache的上傳檔案框架進行上傳
實作效果
以下是程式碼
package com.wangyang.servlet; import java.io.File; import java.io.IOException; import java.util.List; import javax.servlet.ServletException; import javax.servlet.annotation.WebServlet; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.apache.commons.fileupload.FileItem; import org.apache.commons.fileupload.FileUploadException; import org.apache.commons.fileupload.disk.DiskFileItemFactory; import org.apache.commons.fileupload.servlet.ServletFileUpload; @WebServlet("/upload") public class Upload extends HttpServlet { private static final long serialVersionUID = 1L; protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { request.setCharacterEncoding("utf-8"); response.setContentType("text/html;charset=utf-8"); /* InputStream in = request.getInputStream(); BufferedReader br = new BufferedReader(new InputStreamReader(in)); String str = ""; while((str=br.readLine())!=null){ System.out.println(str); } */ System.out.println("[-------------------------------------------------------]"); String filepath=request.getServletContext().getRealPath("/")+"upload/"; File file = new File(filepath); if(!file.exists()) { file.mkdir(); } DiskFileItemFactory factory = new DiskFileItemFactory(); ServletFileUpload upload = new ServletFileUpload(factory); try { List<FileItem> items= upload.parseRequest(request); for(FileItem item: items) { System.out.println(filepath+item.getName()); if(!item.isFormField()) { item.write(new File(filepath+item.getName())); } if(item.isFormField()){ System.out.println(item.getString()); System.out.println(item.getFieldName()); } } } catch (FileUploadException e) { e.printStackTrace(); } catch (Exception e) { // TODO Auto-generated catch block e.printStackTrace(); } response.sendRedirect("index.jsp"); } }
<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%> <!DOCTYPE html> <html> <head> <meta charset="UTF-8"> <meta name="viewport" content="width=device-width, initial-scale=1.0"> <title>Insert title here</title> </head> <body> <form id="user-info" method="post" action="upload" > <input type="file" name="file" multiple> <input type="text" name="username"> <input type="text" name="password"> </form> <button id="sub">提交</button> <script> function createXHR(){ return new XMLHttpRequest(); } var sub = document.getElementById("sub"); sub.onclick=function(){ var xhr = createXHR(); var form = document.getElementById("user-info"); xhr.open("post","upload",true); xhr.send(new FormData(form)); } </script> </body> </html>
這裡沒有進行細節上的編程,只是為了說明簡單原理
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