這篇文章主要介紹了php準確計算復活節日期的方法,涉及php操作日期的技巧,非常具有實用價值,需要的朋友可以參考下
本文實例講述了php準確計算復活節日期的方法。分享給大家供大家參考。具體如下:
<?PHP function isLeapYear( $nYEAR ) { if((($nYEAR % 4 == 0) AND !($nYEAR % 100 == 0)) AND ($nYEAR % 400 != 0)) { return TRUE; } else { return FALSE; } } function p( $a, $b ){ return( $a - ( $a % $b )) / $b; } function easterSunday( $nYEAR ) { // The function is able to calculate the date //of eastersunday back to the year 325, // but mktime() starts at 1970-01-01! if ( $nYEAR < 1970 ) { $dtEasterSunday = mktime( 1,1,1,1,1,1970 ); } else { $nGZ = ( $nYEAR % 19 ) + 1; $nJHD = p( $nYEAR, 100 ) + 1; $nKSJ = p( 3 * $nJHD, 4 ) - 12; $nKORR = p( 8 * $nJHD + 5, 25 ) - 5; $nSO = p( 5 * $nYEAR, 4 ) - $nKSJ - 10; $nEPAKTE = (( 11 * $nGZ + 20 + $nKORR - $nKSJ ) % 30 ); if (( $nEPAKTE == 25 OR $nGZ == 11 ) AND $nEPAKTE == 24 ) { $nEPAKTE = $nEPAKTE + 1; } $nN = 44 - $nEPAKTE; if( $nN < 21 ) { $nN = $nN + 30; } $nN = $nN + 7 - (( $nSO + $nN ) % 7 ); $nN = $nN + isLeapYear( $nYEAR ); $nN = $nN + 59; $nA = isLeapYear( $nYEAR ); // Month $nNM = $nN; if ( $nNM > ( 59 + $nA )) { $nNM = $nNM + 2 - $nA; } $nNM = $nNM + 91; $nMONTH = p( 20 * $nNM, 611 ) - 2; // Day $nNT = $nN; $nNT = $nN; if ( $nNT > ( 59 + $nA )) { $nNT = $nNT + 2 - $nA; } $nNT = $nNT + 91; $nM = p( 20 * $nNT, 611 ); $nDAY = $nNT - p( 611 * $nM, 20 ); $dtEasterSunday = mktime( 0,0,0,$nMONTH,$nDAY,$nYEAR ); } return $dtEasterSunday; } ?>
總結:以上就是這篇文章的全部內容,希望能對大家的學習有所幫助。
相關推薦:
#以上是php實作計算復活節準確日期的方法的詳細內容。更多資訊請關注PHP中文網其他相關文章!