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用SQL進行集合運算

不言
不言原創
2018-06-04 09:29:432231瀏覽

這篇文章主要介紹了用SQL進行集合運算,有著一定的參考價值,現在分享給大家,有需要的朋友可以參考一下

1、比較表和表格

drop table if exists tbl_a;create table tbl_a(
key1 varchar(10),
col_1 int4,
col_2 int4,
col_3 int4
);insert into tbl_a values('A', 2, 3, 4);
insert into tbl_a values('B', 0, 7, 9);
insert into tbl_a values('c', 5, 1, 6);
drop table if exists tbl_b;create table tbl_b(
key1 varchar(10),
col_1 int4,
col_2 int4,
col_3 int4
);
insert into tbl_b values('A', 2, 3, 4);
insert into tbl_b values('B', 0, 7, 9);
insert into tbl_b values('c', 5, 1, 6);-- ## 如果union a b 行数一致则两张表相等 select count(1) row_cnt  from ( select * 
           from tbl_A           union 
          select *            from tbl_b
        ) tmp
;


直接求兩個表的差異

(select * from tbl_a except
 select * from tbl_b) union all
 (select * from tbl_b  except
  select * from tbl_a);

2、用差集實作關係除法運算

建表

drop table if exists skills;create table skills(
skill varchar(10)
);insert into skills values('oracle');
insert into skills values('unix');insert into skills values('java');drop table if exists empskills;create table empskills(
emp varchar(10),
skill varchar(10)
);insert into empskills values('相田','oracle');
insert into empskills values('相田','unix');
insert into empskills values('相田','java');
insert into empskills values('相田','c#');
insert into empskills values('神奇','oracle');
insert into empskills values('神奇','unix');
insert into empskills values('神奇','java');
insert into empskills values('平井','oracle');
insert into empskills values('平井','unix');
insert into empskills values('平井','PHP');
insert into empskills values('平井','Perl');
insert into empskills values('平井','C++');
insert into empskills values('若田部','Perl');
insert into empskills values('度来','oracle');
--把除法变成减法select distinct emp  from empskills es1 where not exists
        (select skill from skills
         expect         select skill from empskills es2          where es1.emp = es2.emp);

3、尋求相等的子集

drop table if exists supparts;create table supparts(
sup varchar(10),
part varchar(10)
);insert into supparts values('A', '螺丝');
insert into supparts values('A', '螺母');
insert into supparts values('A', '管子');
insert into supparts values('B', '螺丝');
insert into supparts values('B', '管子');
insert into supparts values('C', '螺丝');
insert into supparts values('C', '螺母');
insert into supparts values('C', '管子');
insert into supparts values('D', '螺丝');
insert into supparts values('D', '管子');
insert into supparts values('E','保险丝');
insert into supparts values('E', '螺母');
insert into supparts values('E', '管子');
insert into supparts values('F','保险丝');

想法: 兩個供應商都經營同種類型的零件 (簡單的按照零件列進行連接) 兩個供應商的零件類型數相同(即存在一一對映)(count限定)

select a.sup s1, b.sup s2  from supparts a, supparts b where a.sup < b.sup                       -- 生成供应商的全部组合 
   and a.part = b.part                     -- 条件1:经营同种类型的零件 
 group by a.sup, b.suphaving count(*) = (select count(1)         -- 条件2:经营的零件的数量种类相同 a = 中间数                     from supparts c                    where c.sup = a.sup)   and count(*) = (select count(1)         -- 条件2:经营的零件的数量种类相同 b = 中间数                     from supparts d                    where d.sup = b.sup)
;

4、刪除重行

drop table if exists products;create table products(
rowid int4,
name1 varchar(10),
price int4
);insert into products values(1,&#39;苹果&#39;,50);insert into products values(2,&#39;橘子&#39;,100);
insert into products values(3,&#39;橘子&#39;,100);insert into products values(4,&#39;橘子&#39;,100);
insert into products values(5,&#39;香蕉&#39;,80);-- 删除重行高效SQL语句(1):通过EXCEPT求补集delete from productswhere rowid  in (select rowid           -- 全部rowid                   from products 
                 except                 -- 减去                 select max(rowid)      -- 要留下的rowid                   from products                  group by name1, price
                  );-- 删除重行高效SQL语句(2):通过not indelete from products where rowid not in (select max(rowid)                      from products                     group by name1, price
                    );

練習

-- 改进中用union的比较select 
    case when count(1) = (select count(1) from tbl_A)          
    and count(1) = (select count(1)+1 from tbl_b)         
    then count(1) else &#39;不相等&#39; end row_cnt  from ( select * from tbl_A          union 
         select * from tbl_b
        ) tmp
;

內容多來自《SQL進階教材》,只做筆記。練習部分程式碼均為原創。

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