PHP校驗信用卡號實例

*文原創: 2017-12-26 11:13:241639瀏覽

PHP如何實現校驗信用卡卡號碼是否有問題？本文主要介紹了PHP實作透過Luhn演算法校驗信用卡卡號是否有效，透過實例分析了php實作Luhn演算法及相關應用技巧。希望對大家有幫助。

具體實作方法如下：

$numbers = "49927398716 49927398717 1234567812345678 1234567812345670";
foreach (split(&#39; &#39;, $numbers) as $n)
  echo "$n is ", luhnTest($n) ? &#39;valid&#39; : &#39;not valid&#39;, &#39;</br>&#39;;
 
function luhnTest($num) {
  $len = strlen($num);
  for ($i = $len-1; $i >= 0; $i--) {
    $ord = ord($num[$i]);
    if (($len - 1) & $i) {
      $sum += $ord;
    } else {
      $sum += $ord / 5 + (2 * $ord) % 10;
    }
  }   
  return $sum % 10 == 0;
}

#執行結果

49927398716 is valid
49927398717 is not valid
1234567812345678 is not valid
1234567812345670 is valid

下面是一個更簡潔的程式碼：

function luhn_test($num) {
    $str = &#39;&#39;;
    foreach( array_reverse( str_split( $num ) ) as $i => $c ) $str .= ($i % 2 ? $c * 2 : $c );
    return array_sum( str_split($str) ) % 10 == 0;
}
foreach (array(&#39;49927398716&#39;,&#39;49927398717&#39;,&#39;1234567812345678&#39;,&#39;1234567812345670&#39;) as $n)
echo "$n is ", luhn_test($n) ? &#39;valid&#39; : &#39;not valid&#39;, "</br>\n";

輸出結果如下

49927398716 is valid
49927398717 is not valid
1234567812345678 is not valid
1234567812345670 is valid

PHP校驗信用卡號實例

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