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首頁後端開發Python教學[原文]Python教程#資料結構

[原文]Python教程#資料結構

Jul 05, 2017 pm 06:13 PM
python

[譯]The Python Tutorial#Data Structures

5.1 Data Structures

本章節詳細介紹之前介紹過的一些內容,也會介紹一些新的內容。

5.1 More on Lists

列表資料型別擁有更多方法,以下是列表物件的所有方法:

  • list.append(x)
    # 在列表末尾新增項,等同於a[len(a):] = [x]

  • #list.extend(iterable)
    # 加入可迭代物件中所有的項目來擴充列表,等同於a[len(a):] = iterable

  • list.insert(i, x)
    # 在指定位置插入項。第一個參數為元素索引,新的項目會在這個索引之前插入,因此a.insert(0, x)會在列表最前面插入,a.insert(len(a ), x)等同於a.append(x)

  • list.remove(x)
    # 從清單中移除值為x的第一個項,若x不存在,方法拋出例外(ValueError異常)

  • list.pop([i])
    # 從清單中移除指定位置的項目並返回。如果沒有指定索引,a.pop()移除並傳回清單中最後一項。 (方法簽名中包裹i的方括號表示參數是可選的,而不是在這個位置寫一個方括號。這種記號法在Python Library Reference中經常用到)





  • list.clear()
  • 移除清單中的所有項,等同於del a[:]

  • list.index(x[, start[, end]])
  • # 傳回第一個值為x的項的基於0的索引,如果
    x

    不存在拋出
  • ValueError
  • 異常。

    可選參數start
    end被解釋為切片記號法,用來將搜尋限制在列表特定的子列表內。傳回的索引是相對於完整的清單索引,而不是相對於start

    參數。

list.count(x)

傳回清單中x出現的次數 list.sort(key=None, reverse=False)

# 將清單的所有項目進行排序(參數以來自訂排序,請參閱

sorted()

取得更多資訊)

list.reverse()

反轉列表元素

list.copy()

傳回清單的淺拷貝,等同於a[:]

以下是示範清單方法的範例:

<code class="sourceCode python"><span class="op">>>></span> fruits <span class="op">=</span> [<span class="st">'orange'</span>, <span class="st">'apple'</span>, <span class="st">'pear'</span>, <span class="st">'banana'</span>, <span class="st">'kiwi'</span>, <span class="st">'apple'</span>, <span class="st">'banana'</span>]
<span class="op">>>></span> fruits.count(<span class="st">'apple'</span>)
<span class="dv">2</span>
<span class="op">>>></span> fruits.count(<span class="st">'tangerine'</span>)
<span class="dv">0</span>
<span class="op">>>></span> fruits.index(<span class="st">'banana'</span>)
<span class="dv">3</span>
<span class="op">>>></span> fruits.index(<span class="st">'banana'</span>, <span class="dv">4</span>)  <span class="co"># Find next banana starting a position 4</span>
<span class="dv">6</span>
<span class="op">>>></span> fruits.reverse()
<span class="op">>>></span> fruits
[<span class="st">'banana'</span>, <span class="st">'apple'</span>, <span class="st">'kiwi'</span>, <span class="st">'banana'</span>, <span class="st">'pear'</span>, <span class="st">'apple'</span>, <span class="st">'orange'</span>]
<span class="op">>>></span> fruits.append(<span class="st">'grape'</span>)
<span class="op">>>></span> fruits
[<span class="st">'banana'</span>, <span class="st">'apple'</span>, <span class="st">'kiwi'</span>, <span class="st">'banana'</span>, <span class="st">'pear'</span>, <span class="st">'apple'</span>, <span class="st">'orange'</span>, <span class="st">'grape'</span>]
<span class="op">>>></span> fruits.sort()
<span class="op">>>></span> fruits
[<span class="st">'apple'</span>, <span class="st">'apple'</span>, <span class="st">'banana'</span>, <span class="st">'banana'</span>, <span class="st">'grape'</span>, <span class="st">'kiwi'</span>, <span class="st">'orange'</span>, <span class="st">'pear'</span>]
<span class="op">>>></span> fruits.pop()
<span class="co">'pear'</span></code>

諸如
insert, reverse

sort的這樣,只改變了列表但是沒有回傳值列印,它們傳回預設的None

[1 ]
。這是Python可變資料結構適用的設計原則。

5.1.1 Using Lists as Stacks
列表方法使得將其用作堆疊非常容易,堆疊中最後一個加入的元素第一個被釋放(後進先出)。使用

append()

方法加入元素到堆疊頂,使用不含參數的

pop()將堆疊頂元素出棧。範例: <pre class='brush:php;toolbar:false;'>&lt;code class=&quot;sourceCode python&quot;&gt;&lt;span class=&quot;op&quot;&gt;&gt;&gt;&gt;&lt;/span&gt; stack &lt;span class=&quot;op&quot;&gt;=&lt;/span&gt; [&lt;span class=&quot;dv&quot;&gt;3&lt;/span&gt;, &lt;span class=&quot;dv&quot;&gt;4&lt;/span&gt;, &lt;span class=&quot;dv&quot;&gt;5&lt;/span&gt;] &lt;span class=&quot;op&quot;&gt;&gt;&gt;&gt;&lt;/span&gt; stack.append(&lt;span class=&quot;dv&quot;&gt;6&lt;/span&gt;) &lt;span class=&quot;op&quot;&gt;&gt;&gt;&gt;&lt;/span&gt; stack.append(&lt;span class=&quot;dv&quot;&gt;7&lt;/span&gt;) &lt;span class=&quot;op&quot;&gt;&gt;&gt;&gt;&lt;/span&gt; stack [&lt;span class=&quot;dv&quot;&gt;3&lt;/span&gt;, &lt;span class=&quot;dv&quot;&gt;4&lt;/span&gt;, &lt;span class=&quot;dv&quot;&gt;5&lt;/span&gt;, &lt;span class=&quot;dv&quot;&gt;6&lt;/span&gt;, &lt;span class=&quot;dv&quot;&gt;7&lt;/span&gt;] &lt;span class=&quot;op&quot;&gt;&gt;&gt;&gt;&lt;/span&gt; stack.pop() &lt;span class=&quot;dv&quot;&gt;7&lt;/span&gt; &lt;span class=&quot;op&quot;&gt;&gt;&gt;&gt;&lt;/span&gt; stack [&lt;span class=&quot;dv&quot;&gt;3&lt;/span&gt;, &lt;span class=&quot;dv&quot;&gt;4&lt;/span&gt;, &lt;span class=&quot;dv&quot;&gt;5&lt;/span&gt;, &lt;span class=&quot;dv&quot;&gt;6&lt;/span&gt;] &lt;span class=&quot;op&quot;&gt;&gt;&gt;&gt;&lt;/span&gt; stack.pop() &lt;span class=&quot;dv&quot;&gt;6&lt;/span&gt; &lt;span class=&quot;op&quot;&gt;&gt;&gt;&gt;&lt;/span&gt; stack.pop() &lt;span class=&quot;dv&quot;&gt;5&lt;/span&gt; &lt;span class=&quot;op&quot;&gt;&gt;&gt;&gt;&lt;/span&gt; stack [&lt;span class=&quot;dv&quot;&gt;3&lt;/span&gt;, &lt;span class=&quot;dv&quot;&gt;4&lt;/span&gt;]&lt;/code&gt;</pre> 5.1.2 Using Lists as Queues 將清單用作佇列也是可能的,佇列中先加入的元素先釋放(先進先出);然而,這樣用清單效率就非常不高。因為在清單末端新增和取出元素很快,但是在清單開頭插入或刪除元素很慢(因為必須將其他所有元素位移一位)。 經過特殊設計的collections.deque

在首尾兩端新增和刪除元素都很快,可以使用它來實作佇列。範例:
<code class="sourceCode python"><span class="op">>>></span> <span class="im">from</span> collections <span class="im">import</span> deque
<span class="op">>>></span> queue <span class="op">=</span> deque([<span class="st">"Eric"</span>, <span class="st">"John"</span>, <span class="st">"Michael"</span>])
<span class="op">>>></span> queue.append(<span class="st">"Terry"</span>)           <span class="co"># Terry arrives</span>
<span class="op">>>></span> queue.append(<span class="st">"Graham"</span>)          <span class="co"># Graham arrives</span>
<span class="op">>>></span> queue.popleft()                 <span class="co"># The first to arrive now leaves</span>
<span class="co">'Eric'</span>
<span class="op">>>></span> queue.popleft()                 <span class="co"># The second to arrive now leaves</span>
<span class="co">'John'</span>
<span class="op">>>></span> queue                           <span class="co"># Remaining queue in order of arrival</span>
deque([<span class="st">'Michael'</span>, <span class="st">'Terry'</span>, <span class="st">'Graham'</span>])</code>

5.1.3 List Comprehensions
列表推導式為建立清單提供了簡潔方式。一般的應用方式是:建立新列表,列表元素是對其他序列或可迭代物件操作的結果;或建立元素滿足特定條件的子序列。 ### ###假如希望建立平方列表:### ###
<code class="sourceCode python"><span class="op">>>></span> squares <span class="op">=</span> []
<span class="op">>>></span> <span class="cf">for</span> x <span class="op">in</span> <span class="bu">range</span>(<span class="dv">10</span>):
...     squares.append(x<span class="op">**</span><span class="dv">2</span>)
...
<span class="op">>>></span> squares
[<span class="dv">0</span>, <span class="dv">1</span>, <span class="dv">4</span>, <span class="dv">9</span>, <span class="dv">16</span>, <span class="dv">25</span>, <span class="dv">36</span>, <span class="dv">49</span>, <span class="dv">64</span>, <span class="dv">81</span>]</code>
### ###注意以上創建(或重寫)了名為###x###的變量,在循環結束之後仍然存在。使用下列方法可建立沒有任何副作用的平方列表:### ###
<code class="sourceCode python">squares <span class="op">=</span> <span class="bu">list</span>(<span class="bu">map</span>(<span class="kw">lambda</span> x: x<span class="op">**</span><span class="dv">2</span>, <span class="bu">range</span>(<span class="dv">10</span>)))</code>
### ###或者,等用於:### ###
<code class="sourceCode python">squares <span class="op">=</span> [x<span class="op">**</span><span class="dv">2</span> <span class="cf">for</span> x <span class="op">in</span> <span class="bu">range</span>(<span class="dv">10</span>)]</code>
### ###這種方式比較簡潔易讀。 ### ###跟著###for###子句,緊接著零個或多個###for###子句或###if###子句的表達式再加上中括號,構成了列表推導式。其傳回結果是一個新的列表,列表的元素是表達式中###for###和###if###子句的計算結果。例如,以下列表推導式組合兩個列表中不相等的元素:### ###
<code class="sourceCode python"><span class="op">>>></span> [(x, y) <span class="cf">for</span> x <span class="op">in</span> [<span class="dv">1</span>,<span class="dv">2</span>,<span class="dv">3</span>] <span class="cf">for</span> y <span class="op">in</span> [<span class="dv">3</span>,<span class="dv">1</span>,<span class="dv">4</span>] <span class="cf">if</span> x <span class="op">!=</span> y]
[(<span class="dv">1</span>, <span class="dv">3</span>), (<span class="dv">1</span>, <span class="dv">4</span>), (<span class="dv">2</span>, <span class="dv">3</span>), (<span class="dv">2</span>, <span class="dv">1</span>), (<span class="dv">2</span>, <span class="dv">4</span>), (<span class="dv">3</span>, <span class="dv">1</span>), (<span class="dv">3</span>, <span class="dv">4</span>)]</code>
### ###等價於:### ###
<code class="sourceCode python"><span class="op">>>></span> combs <span class="op">=</span> []
<span class="op">>>></span> <span class="cf">for</span> x <span class="op">in</span> [<span class="dv">1</span>,<span class="dv">2</span>,<span class="dv">3</span>]:
...     <span class="cf">for</span> y <span class="op">in</span> [<span class="dv">3</span>,<span class="dv">1</span>,<span class="dv">4</span>]:
...         <span class="cf">if</span> x <span class="op">!=</span> y:
...             combs.append((x, y))
...
<span class="op">>>></span> combs
[(<span class="dv">1</span>, <span class="dv">3</span>), (<span class="dv">1</span>, <span class="dv">4</span>), (<span class="dv">2</span>, <span class="dv">3</span>), (<span class="dv">2</span>, <span class="dv">1</span>), (<span class="dv">2</span>, <span class="dv">4</span>), (<span class="dv">3</span>, <span class="dv">1</span>), (<span class="dv">3</span>, <span class="dv">4</span>)]</code>
###

注意上面两个代码段中forif语句的顺序是相同的。

如果表达式是一个元组(如上所示的(x, y)),必须将其加上括号。

<code class="sourceCode python"><span class="op">>>></span> vec <span class="op">=</span> [<span class="op">-</span><span class="dv">4</span>, <span class="op">-</span><span class="dv">2</span>, <span class="dv">0</span>, <span class="dv">2</span>, <span class="dv">4</span>]
<span class="op">>>></span> <span class="co"># create a new list with the values doubled</span>
<span class="op">>>></span> [x<span class="op">*</span><span class="dv">2</span> <span class="cf">for</span> x <span class="op">in</span> vec]
[<span class="op">-</span><span class="dv">8</span>, <span class="op">-</span><span class="dv">4</span>, <span class="dv">0</span>, <span class="dv">4</span>, <span class="dv">8</span>]
<span class="op">>>></span> <span class="co"># filter the list to exclude negative numbers</span>
<span class="op">>>></span> [x <span class="cf">for</span> x <span class="op">in</span> vec <span class="cf">if</span> x <span class="op">>=</span> <span class="dv">0</span>]
[<span class="dv">0</span>, <span class="dv">2</span>, <span class="dv">4</span>]
<span class="op">>>></span> <span class="co"># apply a function to all the elements</span>
<span class="op">>>></span> [<span class="bu">abs</span>(x) <span class="cf">for</span> x <span class="op">in</span> vec]
[<span class="dv">4</span>, <span class="dv">2</span>, <span class="dv">0</span>, <span class="dv">2</span>, <span class="dv">4</span>]
<span class="op">>>></span> <span class="co"># call a method on each element</span>
<span class="op">>>></span> freshfruit <span class="op">=</span> [<span class="st">'  banana'</span>, <span class="st">'  loganberry '</span>, <span class="st">'passion fruit  '</span>]
<span class="op">>>></span> [weapon.strip() <span class="cf">for</span> weapon <span class="op">in</span> freshfruit]
[<span class="st">'banana'</span>, <span class="st">'loganberry'</span>, <span class="st">'passion fruit'</span>]
<span class="op">>>></span> <span class="co"># create a list of 2-tuples like (number, square)</span>
<span class="op">>>></span> [(x, x<span class="op">**</span><span class="dv">2</span>) <span class="cf">for</span> x <span class="op">in</span> <span class="bu">range</span>(<span class="dv">6</span>)]
[(<span class="dv">0</span>, <span class="dv">0</span>), (<span class="dv">1</span>, <span class="dv">1</span>), (<span class="dv">2</span>, <span class="dv">4</span>), (<span class="dv">3</span>, <span class="dv">9</span>), (<span class="dv">4</span>, <span class="dv">16</span>), (<span class="dv">5</span>, <span class="dv">25</span>)]
<span class="op">>>></span> <span class="co"># the tuple must be parenthesized, otherwise an error is raised</span>
<span class="op">>>></span> [x, x<span class="op">**</span><span class="dv">2</span> <span class="cf">for</span> x <span class="op">in</span> <span class="bu">range</span>(<span class="dv">6</span>)]
  File <span class="st">"<stdin>"</span>, line <span class="dv">1</span>, <span class="op">in</span> <span class="op"><</span>module<span class="op">></span>
    [x, x<span class="op">**</span><span class="dv">2</span> <span class="cf">for</span> x <span class="op">in</span> <span class="bu">range</span>(<span class="dv">6</span>)]
               <span class="op">^</span>
<span class="pp">SyntaxError</span>: invalid syntax
<span class="op">>>></span> <span class="co"># flatten a list using a listcomp with two 'for'</span>
<span class="op">>>></span> vec <span class="op">=</span> [[<span class="dv">1</span>,<span class="dv">2</span>,<span class="dv">3</span>], [<span class="dv">4</span>,<span class="dv">5</span>,<span class="dv">6</span>], [<span class="dv">7</span>,<span class="dv">8</span>,<span class="dv">9</span>]]
<span class="op">>>></span> [num <span class="cf">for</span> elem <span class="op">in</span> vec <span class="cf">for</span> num <span class="op">in</span> elem]
[<span class="dv">1</span>, <span class="dv">2</span>, <span class="dv">3</span>, <span class="dv">4</span>, <span class="dv">5</span>, <span class="dv">6</span>, <span class="dv">7</span>, <span class="dv">8</span>, <span class="dv">9</span>]</code>

列表推导式可以包含复杂的表达式甚至嵌套函数:

<code class="sourceCode python"><span class="op">>>></span> <span class="im">from</span> math <span class="im">import</span> pi
<span class="op">>>></span> [<span class="bu">str</span>(<span class="bu">round</span>(pi, i)) <span class="cf">for</span> i <span class="op">in</span> <span class="bu">range</span>(<span class="dv">1</span>, <span class="dv">6</span>)]
[<span class="st">'3.1'</span>, <span class="st">'3.14'</span>, <span class="st">'3.142'</span>, <span class="st">'3.1416'</span>, <span class="st">'3.14159'</span>]</code>

5.1.4 Nested List Comprehensions

列表推导式开头的表达式可以是任意表达式,包括另一个列表推导式。

考虑以下示例,一个包含3个长度为4的列表的列表实现了3x4的矩阵:

<code class="sourceCode python">matrix <span class="op">=</span> [
    [<span class="dv">1</span>, <span class="dv">2</span>, <span class="dv">3</span>, <span class="dv">4</span>],
    [<span class="dv">5</span>, <span class="dv">6</span>, <span class="dv">7</span>, <span class="dv">8</span>],
    [<span class="dv">9</span>, <span class="dv">10</span>, <span class="dv">11</span>, <span class="dv">12</span>],
]</code>

以下列表推导式反转行列:

<code class="sourceCode python"><span class="op">>>></span> [[row[i] <span class="cf">for</span> row <span class="op">in</span> matrix] <span class="cf">for</span> i <span class="op">in</span> <span class="bu">range</span>(<span class="dv">4</span>)]
[[<span class="dv">1</span>, <span class="dv">5</span>, <span class="dv">9</span>], [<span class="dv">2</span>, <span class="dv">6</span>, <span class="dv">10</span>], [<span class="dv">3</span>, <span class="dv">7</span>, <span class="dv">11</span>], [<span class="dv">4</span>, <span class="dv">8</span>, <span class="dv">12</span>]]</code>

前面的章节提到,嵌套的列表推导式是在其后跟随的for的上下文中求值的,因此这个示例等同于:

<code class="sourceCode python"><span class="op">>>></span> transposed <span class="op">=</span> []
<span class="op">>>></span> <span class="cf">for</span> i <span class="op">in</span> <span class="bu">range</span>(<span class="dv">4</span>):
...     transposed.append([row[i] <span class="cf">for</span> row <span class="op">in</span> matrix])
...
<span class="op">>>></span> transposed
[[<span class="dv">1</span>, <span class="dv">5</span>, <span class="dv">9</span>], [<span class="dv">2</span>, <span class="dv">6</span>, <span class="dv">10</span>], [<span class="dv">3</span>, <span class="dv">7</span>, <span class="dv">11</span>], [<span class="dv">4</span>, <span class="dv">8</span>, <span class="dv">12</span>]]</code>

依次等同于:

<code class="sourceCode python"><span class="op">>>></span> transposed <span class="op">=</span> []
<span class="op">>>></span> <span class="cf">for</span> i <span class="op">in</span> <span class="bu">range</span>(<span class="dv">4</span>):
...     <span class="co"># the following 3 lines implement the nested listcomp</span>
...     transposed_row <span class="op">=</span> []
...     <span class="cf">for</span> row <span class="op">in</span> matrix:
...         transposed_row.append(row[i])
...     transposed.append(transposed_row)
<span class="op">>>></span> transposed
[[<span class="dv">1</span>, <span class="dv">5</span>, <span class="dv">9</span>], [<span class="dv">2</span>, <span class="dv">6</span>, <span class="dv">10</span>], [<span class="dv">3</span>, <span class="dv">7</span>, <span class="dv">11</span>], [<span class="dv">4</span>, <span class="dv">8</span>, <span class="dv">12</span>]]</code>

在实践中,应该选择built-in函数来复合流程语句。在以上的用例中zip()函数更有用:

<code class="sourceCode python"><span class="op">>>></span> <span class="bu">list</span>(<span class="bu">zip</span>(<span class="op">*</span>matrix))
[(<span class="dv">1</span>, <span class="dv">5</span>, <span class="dv">9</span>), (<span class="dv">2</span>, <span class="dv">6</span>, <span class="dv">10</span>), (<span class="dv">3</span>, <span class="dv">7</span>, <span class="dv">11</span>), (<span class="dv">4</span>, <span class="dv">8</span>, <span class="dv">12</span>)]</code>

参见 Unpacking Argument Lists了解关于上面*使用的更多详细信息。

5.2 The del statement

在提供列表索引而不是值的情况下,有一种方法可以移除列表中的元素:del语句。这种方式与返回值的pop()方法不同。del语句也可以用来移除部分列表或者清除整个列表(之前使用将空的列表赋值给列表片段的方式实现)。示例:

<code class="sourceCode python"><span class="op">>>></span> a <span class="op">=</span> [<span class="op">-</span><span class="dv">1</span>, <span class="dv">1</span>, <span class="fl">66.25</span>, <span class="dv">333</span>, <span class="dv">333</span>, <span class="fl">1234.5</span>]
<span class="op">>>></span> <span class="kw">del</span> a[<span class="dv">0</span>]
<span class="op">>>></span> a
[<span class="dv">1</span>, <span class="fl">66.25</span>, <span class="dv">333</span>, <span class="dv">333</span>, <span class="fl">1234.5</span>]
<span class="op">>>></span> <span class="kw">del</span> a[<span class="dv">2</span>:<span class="dv">4</span>]
<span class="op">>>></span> a
[<span class="dv">1</span>, <span class="fl">66.25</span>, <span class="fl">1234.5</span>]
<span class="op">>>></span> <span class="kw">del</span> a[:]
<span class="op">>>></span> a
[]</code>

del也可以用来删除整个变量:

<code class="sourceCode python"><span class="op">>>></span> <span class="kw">del</span> a</code>

此后引用名字a会抛出异常(至少在其他值赋值给名字a之前)。接下来会有更多del的使用

5.3 Tuples and Sequences

列表和字符串有很多常用属性,比如索引和切片操作。它们是序列数据类型(参见 Sequence Types - list, tuple, range)的两种。Python是一种不断进化的语言,其他的序列类型也可以加入。元组是另一种标准的序列数据类型。

元组包含若干由逗号分隔的值,示例:

<code class="sourceCode python"><span class="op">>>></span> t <span class="op">=</span> <span class="dv">12345</span>, <span class="dv">54321</span>, <span class="st">'hello!'</span>
<span class="op">>>></span> t[<span class="dv">0</span>]
<span class="dv">12345</span>
<span class="op">>>></span> t
(<span class="dv">12345</span>, <span class="dv">54321</span>, <span class="st">'hello!'</span>)
<span class="op">>>></span> <span class="co"># Tuples may be nested:</span>
... u <span class="op">=</span> t, (<span class="dv">1</span>, <span class="dv">2</span>, <span class="dv">3</span>, <span class="dv">4</span>, <span class="dv">5</span>)
<span class="op">>>></span> u
((<span class="dv">12345</span>, <span class="dv">54321</span>, <span class="st">'hello!'</span>), (<span class="dv">1</span>, <span class="dv">2</span>, <span class="dv">3</span>, <span class="dv">4</span>, <span class="dv">5</span>))
<span class="op">>>></span> <span class="co"># Tuples are immutable:</span>
... t[<span class="dv">0</span>] <span class="op">=</span> <span class="dv">88888</span>
Traceback (most recent call last):
  File <span class="st">"<stdin>"</span>, line <span class="dv">1</span>, <span class="op">in</span> <span class="op"><</span>module<span class="op">></span>
<span class="pp">TypeError</span>: <span class="st">'tuple'</span> <span class="bu">object</span> does <span class="op">not</span> support item assignment
<span class="op">>>></span> <span class="co"># but they can contain mutable objects:</span>
... v <span class="op">=</span> ([<span class="dv">1</span>, <span class="dv">2</span>, <span class="dv">3</span>], [<span class="dv">3</span>, <span class="dv">2</span>, <span class="dv">1</span>])
<span class="op">>>></span> v
([<span class="dv">1</span>, <span class="dv">2</span>, <span class="dv">3</span>], [<span class="dv">3</span>, <span class="dv">2</span>, <span class="dv">1</span>])</code>

可见,输出的元组总是放在圆括号中,以便于嵌套的元组可以被正确解析;虽然圆括号总是必须的(如果元组是其他更大表达式的一部分),但是在输入元组的时候可以选择使用圆括号。不能对元组的单个项赋值,但是可以创建包含如列表的可变对象的元组。

虽然元组和列表有些相似,但是他们通常以不同的目的,用于不同的场景。元组是不可变的,通常包含不同类型的元素,可以通过拆包操作(参见后续章节)或者索引(或者当元组是命名元组时,甚至可以通过属性来访问)来访问。列表是可变的,通常其元素也是不同类型的,可以通过对列表的迭代访问元素。

构建包含零个或者1个项的元组比较特殊:一种额外的奇怪语法可以适用于这种情况。空元组由一对空的圆括号创建;一个元素的元组由一个跟着逗号的值创建(在圆括号中放入单个值是不够的。译注:这种情况:(1)表示整数而不是元组,使用(1, )表示元组也是可行的)。丑陋但是有效。示例:

<code class="sourceCode python"><span class="op">>>></span> empty <span class="op">=</span> ()
<span class="op">>>></span> singleton <span class="op">=</span> <span class="st">'hello'</span>,    <span class="co"># <-- note trailing comma</span>
<span class="op">>>></span> <span class="bu">len</span>(empty)
<span class="dv">0</span>
<span class="op">>>></span> <span class="bu">len</span>(singleton)
<span class="dv">1</span>
<span class="op">>>></span> singleton
(<span class="st">'hello'</span>,)</code>

语句t = 12345, 54321, 'hello!'是封装元组的一个示例:值12345, 54321hello!被封装到了一个元组中。逆向操作也是可行的:

<code class="sourceCode python"><span class="op">>>></span> x, y, z <span class="op">=</span> t</code>

非常恰当地称之为序列解包,适用于任何在等号右边的序列(译注:等号右操作数)。序列解包要求等号左边待赋值的变量数量与序列包含元素数目相同。注意多重赋值只是封装元组和序列解包的结合(译注:多重赋值:i, j = 1, 2

5.4 Set

Python也包含实现了集合的数据类型。集合是无序不重复的元素集。基本功能包括成员关系测试和重复实体消除。集合对象也支持并集,交集,差集以及对称差集等数学操作。

可以使用花括号和set()函数创建集合。谨记:创建空集合必须使用set函数,不能使用{},后者用于创建空字典。

以下是简单示范:

<code class="sourceCode python"><span class="op">>>></span> basket <span class="op">=</span> {<span class="st">'apple'</span>, <span class="st">'orange'</span>, <span class="st">'apple'</span>, <span class="st">'pear'</span>, <span class="st">'orange'</span>, <span class="st">'banana'</span>}
<span class="op">>>></span> <span class="bu">print</span>(basket)                      <span class="co"># show that duplicates have been removed</span>
{<span class="st">'orange'</span>, <span class="st">'banana'</span>, <span class="st">'pear'</span>, <span class="st">'apple'</span>}
<span class="op">>>></span> <span class="st">'orange'</span> <span class="op">in</span> basket                 <span class="co"># fast membership testing</span>
<span class="va">True</span>
<span class="op">>>></span> <span class="st">'crabgrass'</span> <span class="op">in</span> basket
<span class="va">False</span>

<span class="op">>>></span> <span class="co"># Demonstrate set operations on unique letters from two words</span>
...
<span class="op">>>></span> a <span class="op">=</span> <span class="bu">set</span>(<span class="st">'abracadabra'</span>)
<span class="op">>>></span> b <span class="op">=</span> <span class="bu">set</span>(<span class="st">'alacazam'</span>)
<span class="op">>>></span> a                                  <span class="co"># unique letters in a</span>
{<span class="st">'a'</span>, <span class="st">'r'</span>, <span class="st">'b'</span>, <span class="st">'c'</span>, <span class="st">'d'</span>}
<span class="op">>>></span> a <span class="op">-</span> b                              <span class="co"># letters in a but not in b</span>
{<span class="st">'r'</span>, <span class="st">'d'</span>, <span class="st">'b'</span>}
<span class="op">>>></span> a <span class="op">|</span> b                              <span class="co"># letters in a or b or both</span>
{<span class="st">'a'</span>, <span class="st">'c'</span>, <span class="st">'r'</span>, <span class="st">'d'</span>, <span class="st">'b'</span>, <span class="st">'m'</span>, <span class="st">'z'</span>, <span class="st">'l'</span>}
<span class="op">>>></span> a <span class="op">&</span> b                              <span class="co"># letters in both a and b</span>
{<span class="st">'a'</span>, <span class="st">'c'</span>}
<span class="op">>>></span> a <span class="op">^</span> b                              <span class="co"># letters in a or b but not both</span>
{<span class="st">'r'</span>, <span class="st">'d'</span>, <span class="st">'b'</span>, <span class="st">'m'</span>, <span class="st">'z'</span>, <span class="st">'l'</span>}</code>

与列表推导式相同,Python也支持集合推导式:

<code class="sourceCode python"><span class="op">>>></span> a <span class="op">=</span> {x <span class="cf">for</span> x <span class="op">in</span> <span class="st">'abracadabra'</span> <span class="cf">if</span> x <span class="op">not</span> <span class="op">in</span> <span class="st">'abc'</span>}
<span class="op">>>></span> a
{<span class="st">'r'</span>, <span class="st">'d'</span>}</code>

5.5 Dictionaries

另一个内嵌入Python中的数据结构是字典(参见 Mapping Types - dict)。字典在其他一些语言中被称为“联合存储”或者“联合数组”。与序列不同,序列以一系列数字作索引,字典以作索引,键可以是任何不可变类型;通常使用字符串和数字作为键。只包含字符串,数字或者其他元组的元组也可以作为键;直接或者间接包含可变对象的元组不能作为键。因为列表可以使用索引赋值,切片赋值或者append()以及extend()等方法改变自身,所以列表不能作为键。

最好的理解字典的方式是将其认为是键值对的无序集合,同一集合中键唯一。一对花括号创建空字典:{}。在花括号中放置由逗号分隔键值对列表可以为字典添加初始键值对;这也是字典输出的格式。

字典提供的主要操作是:使用键存储值以及取值。可以使用del删除一个键值对。如果使用已经存在的键来存储值,那么与键关联的旧值会被重写。使用不存在的键来取值会抛出异常。

在字典上执行list(d.keys())返回字典所有键的无序列表(使用sorted(d.keys())使其有序)[2]。使用关键字in检查键在字典中是否存在。

以下是使用字典的示例:

<code class="sourceCode python"><span class="op">>>></span> tel <span class="op">=</span> {<span class="st">'jack'</span>: <span class="dv">4098</span>, <span class="st">'sape'</span>: <span class="dv">4139</span>}
<span class="op">>>></span> tel[<span class="st">'guido'</span>] <span class="op">=</span> <span class="dv">4127</span>
<span class="op">>>></span> tel
{<span class="st">'sape'</span>: <span class="dv">4139</span>, <span class="st">'guido'</span>: <span class="dv">4127</span>, <span class="st">'jack'</span>: <span class="dv">4098</span>}
<span class="op">>>></span> tel[<span class="st">'jack'</span>]
<span class="dv">4098</span>
<span class="op">>>></span> <span class="kw">del</span> tel[<span class="st">'sape'</span>]
<span class="op">>>></span> tel[<span class="st">'irv'</span>] <span class="op">=</span> <span class="dv">4127</span>
<span class="op">>>></span> tel
{<span class="st">'guido'</span>: <span class="dv">4127</span>, <span class="st">'irv'</span>: <span class="dv">4127</span>, <span class="st">'jack'</span>: <span class="dv">4098</span>}
<span class="op">>>></span> <span class="bu">list</span>(tel.keys())
[<span class="st">'irv'</span>, <span class="st">'guido'</span>, <span class="st">'jack'</span>]
<span class="op">>>></span> <span class="bu">sorted</span>(tel.keys())
[<span class="st">'guido'</span>, <span class="st">'irv'</span>, <span class="st">'jack'</span>]
<span class="op">>>></span> <span class="st">'guido'</span> <span class="op">in</span> tel
<span class="va">True</span>
<span class="op">>>></span> <span class="st">'jack'</span> <span class="op">not</span> <span class="op">in</span> tel
<span class="va">False</span></code>

dict()构造器直接使用键值对序列构造字典:

<code class="sourceCode python"><span class="op">>>></span> <span class="bu">dict</span>([(<span class="st">'sape'</span>, <span class="dv">4139</span>), (<span class="st">'guido'</span>, <span class="dv">4127</span>), (<span class="st">'jack'</span>, <span class="dv">4098</span>)])
{<span class="st">'sape'</span>: <span class="dv">4139</span>, <span class="st">'jack'</span>: <span class="dv">4098</span>, <span class="st">'guido'</span>: <span class="dv">4127</span>}</code>

此外,字典推导式可以从任意键值表达式中创建字典:

<code class="sourceCode python"><span class="op">>>></span> {x: x<span class="op">**</span><span class="dv">2</span> <span class="cf">for</span> x <span class="op">in</span> (<span class="dv">2</span>, <span class="dv">4</span>, <span class="dv">6</span>)}
{<span class="dv">2</span>: <span class="dv">4</span>, <span class="dv">4</span>: <span class="dv">16</span>, <span class="dv">6</span>: <span class="dv">36</span>}</code>

当键是简单的字符串时,可以使用关键字参数来指定键值对:

<code class="sourceCode python"><span class="op">>>></span> <span class="bu">dict</span>(sape<span class="op">=</span><span class="dv">4139</span>, guido<span class="op">=</span><span class="dv">4127</span>, jack<span class="op">=</span><span class="dv">4098</span>)
{<span class="st">'sape'</span>: <span class="dv">4139</span>, <span class="st">'jack'</span>: <span class="dv">4098</span>, <span class="st">'guido'</span>: <span class="dv">4127</span>}</code>

5.6 Looping Techniques

遍历字典时,使用items()方法可以同时检索键及其对应的值。

<code class="sourceCode python"><span class="op">>>></span> knights <span class="op">=</span> {<span class="st">'gallahad'</span>: <span class="st">'the pure'</span>, <span class="st">'robin'</span>: <span class="st">'the brave'</span>}
<span class="op">>>></span> <span class="cf">for</span> k, v <span class="op">in</span> knights.items():
...     <span class="bu">print</span>(k, v)
...
gallahad the pure
robin the brave</code>

遍历序列时,使用enumerate()函数可以同时检索位置索引及其对应的值:

<code class="sourceCode python"><span class="op">>>></span> <span class="cf">for</span> i, v <span class="op">in</span> <span class="bu">enumerate</span>([<span class="st">'tic'</span>, <span class="st">'tac'</span>, <span class="st">'toe'</span>]):
...     <span class="bu">print</span>(i, v)
...
<span class="dv">0</span> tic
<span class="dv">1</span> tac
<span class="dv">2</span> toe</code>

同时遍历两个或者更多序列时,使用zip()函数可以将元素组成对:

<code class="sourceCode python"><span class="op">>>></span> questions <span class="op">=</span> [<span class="st">'name'</span>, <span class="st">'quest'</span>, <span class="st">'favorite color'</span>]
<span class="op">>>></span> answers <span class="op">=</span> [<span class="st">'lancelot'</span>, <span class="st">'the holy grail'</span>, <span class="st">'blue'</span>]
<span class="op">>>></span> <span class="cf">for</span> q, a <span class="op">in</span> <span class="bu">zip</span>(questions, answers):
...     <span class="bu">print</span>(<span class="st">'What is your </span><span class="sc">{0}</span><span class="st">?  It is </span><span class="sc">{1}</span><span class="st">.'</span>.<span class="bu">format</span>(q, a))
...
What <span class="op">is</span> your name?  It <span class="op">is</span> lancelot.
What <span class="op">is</span> your quest?  It <span class="op">is</span> the holy grail.
What <span class="op">is</span> your favorite color?  It <span class="op">is</span> blue.</code>

需要逆序遍历序列时,首先指定一个正向的序列,然后调用reversed()函数:

<code class="sourceCode python"><span class="op">>>></span> <span class="cf">for</span> i <span class="op">in</span> <span class="bu">reversed</span>(<span class="bu">range</span>(<span class="dv">1</span>, <span class="dv">10</span>, <span class="dv">2</span>)):
...     <span class="bu">print</span>(i)
...
<span class="dv">9</span>
<span class="dv">7</span>
<span class="dv">5</span>
<span class="dv">3</span>
<span class="dv">1</span></code>

需要以特定顺序遍历序列时,使用sorted()函数返回新的有序序列,原序列不会改动:

<code class="sourceCode python"><span class="op">>>></span> basket <span class="op">=</span> [<span class="st">'apple'</span>, <span class="st">'orange'</span>, <span class="st">'apple'</span>, <span class="st">'pear'</span>, <span class="st">'orange'</span>, <span class="st">'banana'</span>]
<span class="op">>>></span> <span class="cf">for</span> f <span class="op">in</span> <span class="bu">sorted</span>(<span class="bu">set</span>(basket)):
...     <span class="bu">print</span>(f)
...
apple
banana
orange
pear</code>

有时需要在遍历序列的同时修改序列,创建新的替代序列更加简单并且安全:

<code class="sourceCode python"><span class="op">>>></span> <span class="im">import</span> math
<span class="op">>>></span> raw_data <span class="op">=</span> [<span class="fl">56.2</span>, <span class="bu">float</span>(<span class="st">'NaN'</span>), <span class="fl">51.7</span>, <span class="fl">55.3</span>, <span class="fl">52.5</span>, <span class="bu">float</span>(<span class="st">'NaN'</span>), <span class="fl">47.8</span>]
<span class="op">>>></span> filtered_data <span class="op">=</span> []
<span class="op">>>></span> <span class="cf">for</span> value <span class="op">in</span> raw_data:
...     <span class="cf">if</span> <span class="op">not</span> math.isnan(value):
...         filtered_data.append(value)
...
<span class="op">>>></span> filtered_data
[<span class="fl">56.2</span>, <span class="fl">51.7</span>, <span class="fl">55.3</span>, <span class="fl">52.5</span>, <span class="fl">47.8</span>]</code>

5.7 More on Conditions

whileif语句中使用的条件可以包含任意操作符,不仅仅是比较运算符。

比较运算符innot in检查指定值在序列中是否存在(不存在)。操作符isis not比较两个对象是否真正相同(内存地址比较);这两个操作符只对像列表那样的可变对象重要。所有的比较运算符拥有相同的优先级,并且都低于数字运算符。

比较运算符可以链接起来。例如a 测试<code>b是否大于a同时b等于c(译注:同其他高级语言的:a )

比较运算符可以结合布尔运算符andor使用,比较的结果(或者其他任何布尔表达式)可以使用not来作否定。and,ornot优先级比比较运算符低;其中not的优先级最高而or优先级最低,因此A and not B or C等同于(A and (not B)) or C。一如既往,可以使用圆括号表述想要的优先级顺序。

布尔运算符andor号称短路运算符:它们的参数从左向右求值,一旦结果确定,求值过程就会停止。例如,如果AC是真,B是假,A and B and C不会对表达式C求值(译注:A and B为假,已经确定了整个表达式A and B and C的值为假,表达式C的值对结果不会造成影响,因此不会对其求值)。当用作一般值而不是布尔值时,短路操作的返回值是最后一个求值的参数。

可以将比较运算或者布尔表达式赋值给变量:

<code class="sourceCode python"><span class="op">>>></span> string1, string2, string3 <span class="op">=</span> <span class="st">''</span>, <span class="st">'Trondheim'</span>, <span class="st">'Hammer Dance'</span>
<span class="op">>>></span> non_null <span class="op">=</span> string1 <span class="op">or</span> string2 <span class="op">or</span> string3
<span class="op">>>></span> non_null
<span class="co">'Trondheim'</span></code>

注意在Python中,赋值操作不能像C语言一样在表达式内发生。C程序员也许会抱怨,但是这避免了C程序中遇到的一个普遍问题:当想要表示==时候可能误用了=

5.8 Comparing Sequences and Other Types

相同序列类型之间的序列对象可以相互比较。比较使用字典序:首先比较两个序列的第一项,如果它们不同,比较运算的结果就可确定了;如果它们不同,比较两个序列中的下一个项,以此类推,直到其中一个序列耗尽。如果被比较的两个项是同一类型的,那么使用字典序递归比较。如果两个序列的所有项都是相等的,那么他们相等。如果其中一个序列是另一个序列的子序列,那么短的一个序列较小。字符串的字典序使用Unicode代码点数字排序单个字符。

以下是相同类型的序列对象之间的比较示例:

<code class="sourceCode python">(<span class="dv">1</span>, <span class="dv">2</span>, <span class="dv">3</span>)              <span class="op"><</span> (<span class="dv">1</span>, <span class="dv">2</span>, <span class="dv">4</span>)
[<span class="dv">1</span>, <span class="dv">2</span>, <span class="dv">3</span>]              <span class="op"><</span> [<span class="dv">1</span>, <span class="dv">2</span>, <span class="dv">4</span>]
<span class="co">'ABC'</span> <span class="op"><</span> <span class="st">'C'</span> <span class="op"><</span> <span class="st">'Pascal'</span> <span class="op"><</span> <span class="st">'Python'</span>
(<span class="dv">1</span>, <span class="dv">2</span>, <span class="dv">3</span>, <span class="dv">4</span>)           <span class="op"><</span> (<span class="dv">1</span>, <span class="dv">2</span>, <span class="dv">4</span>)
(<span class="dv">1</span>, <span class="dv">2</span>)                 <span class="op"><</span> (<span class="dv">1</span>, <span class="dv">2</span>, <span class="op">-</span><span class="dv">1</span>)
(<span class="dv">1</span>, <span class="dv">2</span>, <span class="dv">3</span>)             <span class="op">==</span> (<span class="fl">1.0</span>, <span class="fl">2.0</span>, <span class="fl">3.0</span>)
(<span class="dv">1</span>, <span class="dv">2</span>, (<span class="st">'aa'</span>, <span class="st">'ab'</span>))   <span class="op"><</span> (<span class="dv">1</span>, <span class="dv">2</span>, (<span class="st">'abc'</span>, <span class="st">'a'</span>), <span class="dv">4</span>)</code>

注意当不同类型对象之间有合适的比较方式时,使用或者<code>>比较不同类型的对象是合法的。例如,混合数字类型之间的比较是根据其数字上的值,0等于0.0。否则,解释器会抛出TypeException异常,而不是随意提供结果

Footnotes

[1] 其他语言可能返回改变后的对象,从而允许方法链接,如:d->insert("a")>remove("b")->sort();
[2] 调用d.keys()返回一个dictionary view对象。从而支持如成员关系测试和迭代之类的操作,但是其内容并不是独立于原始字典的,只是一个视图

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