heapq 模組提供了堆演算法。 heapq是一種子節點和父節點排序的樹狀資料結構。這個模組提供heap[k]
列印heapq 類型
import math import random from cStringIO import StringIO def show_tree(tree, total_width=36, fill=' '): output = StringIO() last_row = -1 for i, n in enumerate(tree): if i: row = int(math.floor(math.log(i+1, 2))) else: row = 0 if row != last_row: output.write('\n') columns = 2**row col_width = int(math.floor((total_width * 1.0) / columns)) output.write(str(n).center(col_width, fill)) last_row = row print output.getvalue() print '-' * total_width print return data = random.sample(range(1,8), 7) print 'data: ', data show_tree(data)
列印結果
data: [3, 2, 6, 5, 4, 7, 1] 3 2 6 5 4 7 1 ------------------------- heapq.heappush(heap, item)
push一個元素到heap裡, 修改上面的程式碼
heap = [] data = random.sample(range(1,8), 7) print 'data: ', data for i in data: print 'add %3d:' % i heapq.heappush(heap, i) show_tree(heap)
列印結果
data: [6, 1, 5, 4, 3, 7, 2] add 6: 6 ------------------------------------ add 1: 1 6 ------------------------------------ add 5: 1 6 5 ------------------------------------ add 4: 1 4 5 6 ------------------------------------ add 3: 1 3 5 6 4 ------------------------------------ add 7: 1 3 5 6 4 7 ------------------------------------ add 2: 1 3 2 6 4 7 5 ------------------------------------
根據結果可以了解,子節點的元素大於父節點元素。而兄弟節點則不會排序。
heapq.heapify(list)
將list類型轉換為heap, 在線性時間內, 重新排列清單。
print 'data: ', data heapq.heapify(data) print 'data: ', data show_tree(data)
列印結果
#data: [2, 7, 4, 3, 6, 5, 1] data: [1, 3, 2, 7, 6, 5, 4] 1 3 2 7 6 5 4 ------------------------------------ heapq.heappop(heap)
刪除並傳回堆中最小的元素, 通過heapify() 和heappop()來排序。
data = random.sample(range(1, 8), 7) print 'data: ', data heapq.heapify(data) show_tree(data) heap = [] while data: i = heapq.heappop(data) print 'pop %3d:' % i show_tree(data) heap.append(i) print 'heap: ', heap
列印結果
#data: [4, 1, 3, 7, 5, 6, 2] 1 4 2 7 5 6 3 ------------------------------------ pop 1: 2 4 3 7 5 6 ------------------------------------ pop 2: 3 4 6 7 5 ------------------------------------ pop 3: 4 5 6 7 ------------------------------------ pop 4: 5 7 6 ------------------------------------ pop 5: 6 7 ------------------------------------ pop 6: 7 ------------------------------------ pop 7: ------------------------------------ heap: [1, 2, 3, 4, 5, 6, 7]
可以看到已排好序的heap。
heapq.heapreplace(iterable, n)
#刪除現有元素並將其替換為新值。
data = random.sample(range(1, 8), 7) print 'data: ', data heapq.heapify(data) show_tree(data) for n in [8, 9, 10]: smallest = heapq.heapreplace(data, n) print 'replace %2d with %2d:' % (smallest, n) show_tree(data)
列印結果
#data: [7, 5, 4, 2, 6, 3, 1] 1 2 3 5 6 7 4 ------------------------------------ replace 1 with 8: 2 5 3 8 6 7 4 ------------------------------------ replace 2 with 9: 3 5 4 8 6 7 9 ------------------------------------ replace 3 with 10: 4 5 7 8 6 10 9 ------------------------------------
heapq.nlargest(n, iterable ) 和heapq.nsmallest(n, iterable)
傳回列表中的n個最大值和最小值
data = range(1,6) l = heapq.nlargest(3, data) print l # [5, 4, 3] s = heapq.nsmallest(3, data) print s # [1, 2, 3]
PS:一個計算題
建構元素個數為K=5 的最小堆程式碼實例:
#!/usr/bin/env python # -*- encoding: utf-8 -*- # Author: kentzhan # import heapq import random heap = [] heapq.heapify(heap) for i in range(15): item = random.randint(10, 100) print "comeing ", item, if len(heap) >= 5: top_item = heap[0] # smallest in heap if top_item < item: # min heap top_item = heapq.heappop(heap) print "pop", top_item, heapq.heappush(heap, item) print "push", item, else: heapq.heappush(heap, item) print "push", item, pass print heap pass print heap print "sort" heap.sort() print heap
結果:
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