javascript - 這個post提交方式哪裡寫的不對呢？
- WBOY原創
- 2016-08-18 09:15:491217瀏覽
提交後插入不了資料 是我ajax寫的不對吧？
tt.php
<code><!DOCTYPE html>
<html>
<head>
<title></title>
<script type="text/javascript">
function ajax(url,data,funsucc){
var oAjax=new XMLHttpRequest();
oAjax.open('POST',url,true);
oAjax.setRequestHeader("Content-Type","application/x-www-form-urlencoded;charset=UTF-8");
oAjax.send("aa="+data);
oAjax.onreadystatechange=function(){
if(oAjax.readyState==4){
if(oAjax.status==200){
funsucc(oAjax.responseText);
}
}
}
}
</script>
<script type="text/javascript">
window.onload=function(){
var oTxt=document.getElementById('txt1');
var oBtn=document.getElementById('btn1');
oBtn.onclick=function(){
ajax("ajax.php",oTxt.value,function(){
window.location.reload();
});
}
}
</script>
</head>
<body>
<form method="post">
<input type="text" id="txt1">
<button id="btn1" type="submit">提交</button>
</form>
</body>
</html></code>
ajax.php
<code><?php
$pdo=new PDO("mysql:host=localhost;dbname=t1","root","");
$txt=$_POST["aa"];
$stmt=$pdo->prepare("insert into ajax(txt)values(?)");
$stmt->execute(array($txt));
?></code>
回覆內容：
提交後插入不了資料 是我ajax寫的不對吧？
tt.php
<code><!DOCTYPE html>
<html>
<head>
<title></title>
<script type="text/javascript">
function ajax(url,data,funsucc){
var oAjax=new XMLHttpRequest();
oAjax.open('POST',url,true);
oAjax.setRequestHeader("Content-Type","application/x-www-form-urlencoded;charset=UTF-8");
oAjax.send("aa="+data);
oAjax.onreadystatechange=function(){
if(oAjax.readyState==4){
if(oAjax.status==200){
funsucc(oAjax.responseText);
}
}
}
}
</script>
<script type="text/javascript">
window.onload=function(){
var oTxt=document.getElementById('txt1');
var oBtn=document.getElementById('btn1');
oBtn.onclick=function(){
ajax("ajax.php",oTxt.value,function(){
window.location.reload();
});
}
}
</script>
</head>
<body>
<form method="post">
<input type="text" id="txt1">
<button id="btn1" type="submit">提交</button>
</form>
</body>
</html></code>
ajax.php
<code><?php
$pdo=new PDO("mysql:host=localhost;dbname=t1","root","");
$txt=$_POST["aa"];
$stmt=$pdo->prepare("insert into ajax(txt)values(?)");
$stmt->execute(array($txt));
?></code>
1、提交按鈕點擊預設會觸發onsubmit事件，而你給它綁定的onclick事件裡沒有取消預設事件；
<code>oBtn.onclick=function(e){
var e=window.event||e;
e.preventDefault&&e.preventDefault();
e.returnValue&&e.returnValue=false;
}</code>
2、採用預設onsubmit，無視ajax，txt1加上name="aa"；
<code>function ajax(url,data,funsucc){
var oAjax=new XMLHttpRequest();
oAjax.open('POST',url,true);
oAjax.setRequestHeader("Content-Type","application/x-www-form-urlencoded;charset=UTF-8");
oAjax.send("aa="+data);//在这里打个断点看看
oAjax.onreadystatechange=function(){
if(oAjax.readyState==4){
if(oAjax.status==200){
funsucc(oAjax.responseText);
}
}
}
}</code>
ajax這個函數這樣改：
<code>function ajax(url,data,funsucc){
var oAjax=new XMLHttpRequest();
oAjax.open('POST',url,true);
oAjax.setRequestHeader("Content-Type","application/x-www-form-urlencoded;charset=UTF-8");
oAjax.onreadystatechange=function(){
if(oAjax.readyState==4){
if(oAjax.status==200){
funsucc(oAjax.responseText);
}
}
}
oAjax.send("aa="+data);
}</code>
異步調用，不然資料發送不出去
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