計算2000年01月01日起到指定日的天數_PHP教程

這是一個計算2000年01月01日起到指定日的天數的函數


(算頭也算尾)日期格式為：YYYY-MM-DD



//    計算從2000年01月01日開始到某日的天數

function cal_start2end($end_day,$start_day)
function cal_start2end($end_day,$start_day)
{
{
🎜>
$start_day=ereg_replace("-","",$start_day);
$end_day=ereg_replace("-","",$end_day);



if($end_day>=$start_day)
{    //    截止日期比起開始日期
    if(substr($end_day,0,4)==substr($start_day,0,4))         {

if( is_int(substr($end_day,0,4)/4) )
    $leap_day=29；


//            //上一年

        if      {
//            the same month  
            ,  }
        其他
            {
//          switch (substr($end_day,4,2))
                {               地      休息；
                案例中」02":
      str($end_day,6,2) 31;
休息；
                案例中"03":
           ) $leap_day 31;
                                              $endday_from_newyear=substr( $end_day,6,2) 1 $leap_day 31*2;
                       🎜>                       $endday_from_newyear=substr($end_day,6,2) 1 $leap_day_from_newyear=substr($end_day,6,2) 1 $leap_day 31*230;
                        休息；
                案例"06":
                       $endday_from_newyear=substr($end_day,6,2) 1 $leap_day 31*3 30;
                        休息；
                案例"07":
                       $endday_from_newyear=substr($end_day,6,            休息；
                   天_from_newyear=substr($end_day,6, 2) 1 $leap_day 31*3 30*2;
                       🎜>                       $endday_from_newyear=substr($end_day,6,2) 1 $leap_day_from_newyear=substr($end_day,6,2) 1 $leap_day 31*2;
                        休息；
       $endday_from_newyear=substr($end_day,6,2) 1 $leap_day 31*5 30*3;
                    案例"11":
                     地1 $leap_day 31*5 30*4;
                         >                       $endday_from_newyear=substr($end_day,6,2) 1 $leap_day 31*5 300*5                         休息；
         _from_startday=$endday_from_newyear;
            }

return ($endday_from_？ >        {
//         不同的年份！

$differ_year=substr($end_day,0,4)-substr($start_day,0,4);

$how_int_4_floor=floor($differ_year/4) 1; // 向下取整
$how_int_4_ceil=ceil($differ_year/4) 1; // 向上取整



if($how_int_4_floor==$how_int_4_ceil)
    $how_leap_year=$how_int_4_floor>    $how_leap_year=$how_int_4_floor-1;
其他
    $how_leap_year=$how_int_4_floor;

$how_noleap_year=$differ_year-$how_leap_year;

$differ_year2day=$how_noleap_year*365 $how_leap_year*366;



if( is_int(substr($end_day,0,4)/4) )
    $leap_day=29;    //閏年
else
    $leap_day=28;



        if(substr($end_day,4,2)==substr($start_day,4,2)) $endday_from_startday =$differ_year2day substr($end_day,4,2);

            }
        其他
            {
//          switch (substr($end_day,4,2))
                {               地      休息；
                案例中」02":
      str($end_day,6,2) 1 31;
                        休息；
                      $endday_from_newyear=substr($end_day,6,2) 1 $leap_day 31;
                    案例"04":
                substr($end_day,6,2) 1 $leap_day 31*2;
                                 5":
                    以30;
                        休息；
                案例"06":
                       $endday_from_newyear=substr($end_day,6,2) 1 $leap_day 31*3 30;
                        休息；
                案例"07" :
             會             休息；
                 $endday_from_newyear=substr($end_day, 6,2) 1 $leap_day 31*3 30*2;
                       
                       $endday_from_newyear=substr($end_day,6,2) 1 $leap_day_from_newyear=substr($end_day,6,2) 1 $leap_day 31*530* 2;
                        的休息下；
     $endday_from_newyear=substr($end_day,6,2) 1 $leap_day 31*5 30*3;
                    案例"11":
                     地1 $leap_day 31*5 30*4;
                         >                       $endday_from_newyear=substr($end_day,6,2) 1 $leap_day 31*5 300*5                         休息；
         _from_startday=$endday_from_newyear $differ_year2day;
    }    //不同月結束  



return🎜>return ($endday_from_startday);


        } // 年末
}        ///$0 >

$start_day="2000-01-01";

$end_day="2011-01-01";

echo "您輸入的是：". $end_day."
n";
$endday_from_startday=cal_start2end($end_day,$start_day);

echo "該日距離$start_day 共".$endday_from_startday." 天";🎜 >
？ >




時間太少了，那個大蝦可以修改為計算任兩個日期之間的間隔最好！ ！ ！ ！ ！ 



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