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,JSON显示多余的东西

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2016-06-23 13:36:511076瀏覽

$result=$menu->show_twoMenu(4);
$col_jobs = array();
$i=0;
while(@$row=mysqli_fetch_array($result)){
$col_jobs[$i] = $row;
$i++;
}
$col_jobs = json_encode($col_jobs);
echo '{"coljobs":'.$col_jobs.'}';
输出却是:
{
    "coljobs": [
        {
            "0": "5",
            "1": "清蒸桂鱼",
            "2": "4",
            "3": "abc.jpeg",
            "4": "124",
            "5": "100",
            "6": "例",
            "7": "80",
            "8": "999",
            "id": "5",
            "Name": "清蒸桂鱼",
            "ParentID": "4",
            "Image": "abc.jpeg",
            "Discount": "124",
            "Price": "100",
            "Unit": "例",
            "Sale": "80",
            "Stock": "999"
        }
    ]
}
为什么会有
            "0": "5",
            "1": "清蒸桂鱼",
            "2": "4",
            "3": "abc.jpeg",
            "4": "124",
            "5": "100",
            "6": "例",
            "7": "80",
            "8": "999",
我不想要,怎么办?


回复讨论(解决方案)

mysqli_fetch_array 返回的是下标数组和关联数组的混合体
按你的需要应使用 mysqli_fetch_assoc 只返回关联数组

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