首頁 >web前端 >js教程 >jQuery取得某天的農曆日期並判斷是否除夕或新年的方法_jquery

jQuery取得某天的農曆日期並判斷是否除夕或新年的方法_jquery

WBOY
WBOY原創
2016-05-16 15:12:542751瀏覽

本文實例講述了jQuery獲取某天的農曆日期並判斷是否除夕或新年的方法。分享給大家參考,具體如下:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<script src="jquery.min.js" type="text/javascript"></script>
<script type="text/javascript">
  //------------------- Begin ----------------------
  CalendarHelper={};
  CalendarHelper.GetCNDate = function (D) {
    var CalendarData = new Array(100);
    var madd = new Array(12);
    var tgString = "甲乙丙丁戊己庚辛壬癸";
    var dzString = "子丑寅卯辰巳午未申酉戌亥";
    var numString = "一二三四五六七八九十";
    var monString = "正二三四五六七八九十冬腊";
    var weekString = "日一二三四五六";
    var sx = "鼠牛虎兔龙蛇马羊猴鸡狗猪";
    var cYear, cMonth, cDay, TheDate;
    CalendarData = new Array(0xA4B, 0x5164B, 0x6A5, 0x6D4, 0x415B5, 0x2B6, 0x957, 0x2092F, 0x497, 0x60C96, 0xD4A, 0xEA5, 0x50DA9, 0x5AD, 0x2B6, 0x3126E, 0x92E, 0x7192D, 0xC95, 0xD4A, 0x61B4A, 0xB55, 0x56A, 0x4155B, 0x25D, 0x92D, 0x2192B, 0xA95, 0x71695, 0x6CA, 0xB55, 0x50AB5, 0x4DA, 0xA5B, 0x30A57, 0x52B, 0x8152A, 0xE95, 0x6AA, 0x615AA, 0xAB5, 0x4B6, 0x414AE, 0xA57, 0x526, 0x31D26, 0xD95, 0x70B55, 0x56A, 0x96D, 0x5095D, 0x4AD, 0xA4D, 0x41A4D, 0xD25, 0x81AA5, 0xB54, 0xB6A, 0x612DA, 0x95B, 0x49B, 0x41497, 0xA4B, 0xA164B, 0x6A5, 0x6D4, 0x615B4, 0xAB6, 0x957, 0x5092F, 0x497, 0x64B, 0x30D4A, 0xEA5, 0x80D65, 0x5AC, 0xAB6, 0x5126D, 0x92E, 0xC96, 0x41A95, 0xD4A, 0xDA5, 0x20B55, 0x56A, 0x7155B, 0x25D, 0x92D, 0x5192B, 0xA95, 0xB4A, 0x416AA, 0xAD5, 0x90AB5, 0x4BA, 0xA5B, 0x60A57, 0x52B, 0xA93, 0x40E95);
    madd[0] = 0;
    madd[1] = 31;
    madd[2] = 59;
    madd[3] = 90;
    madd[4] = 120;
    madd[5] = 151;
    madd[6] = 181;
    madd[7] = 212;
    madd[8] = 243;
    madd[9] = 273;
    madd[10] = 304;
    madd[11] = 334;
    function GetBit(m, n) {
      return (m >> n) & 1;
    }
    function e2c() {
      TheDate = (arguments.length != 3) &#63; new Date() : new Date(arguments[0], arguments[1], arguments[2]);
      var total, m, n, k;
      var isEnd = false;
      var tmp = TheDate.getYear();
      if (tmp < 1900) {
        tmp += 1900;
      }
      total = (tmp - 1921) * 365 + Math.floor((tmp - 1921) / 4) + madd[TheDate.getMonth()] + TheDate.getDate() - 38;
      if (TheDate.getYear() % 4 == 0 && TheDate.getMonth() > 1) {
        total++;
      }
      for (m = 0; ; m++) {
        k = (CalendarData[m] < 0xfff) &#63; 11 : 12;
        for (n = k; n >= 0; n--) {
          if (total <= 29 + GetBit(CalendarData[m], n)) {
            isEnd = true; break;
          }
          total = total - 29 - GetBit(CalendarData[m], n);
        }
        if (isEnd) break;
      }
      cYear = 1921 + m;
      cMonth = k - n + 1;
      cDay = total;
      if (k == 12) {
        if (cMonth == Math.floor(CalendarData[m] / 0x10000) + 1) {
          cMonth = 1 - cMonth;
        }
        if (cMonth > Math.floor(CalendarData[m] / 0x10000) + 1) {
          cMonth--;
        }
      }
    }
    function GetcDateString() {
      var tmp = "";
      tmp += tgString.charAt((cYear - 4) % 10);
      tmp += dzString.charAt((cYear - 4) % 12);
      tmp += "(";
      tmp += sx.charAt((cYear - 4) % 12);
      tmp += ")年 ";
      if (cMonth < 1) {
        tmp += "(闰)";
        tmp += monString.charAt(-cMonth - 1);
      } else {
        tmp += monString.charAt(cMonth - 1);
      }
      tmp += "月";
      tmp += (cDay < 11) &#63; "初" : ((cDay < 20) &#63; "十" : ((cDay < 30) &#63; "廿" : "三十"));
      if (cDay % 10 != 0 || cDay == 10) {
        tmp += numString.charAt((cDay - 1) % 10);
      }
      return tmp;
    }
    function GetLunarDay(solarYear, solarMonth, solarDay) {
      //solarYear = solarYear<1900&#63;(1900+solarYear):solarYear;
      if (solarYear < 1921 || solarYear > 2020) {
        return "";
      } else {
        solarMonth = (parseInt(solarMonth) > 0) &#63; (solarMonth - 1) : 11;
        e2c(solarYear, solarMonth, solarDay);
        return GetcDateString();
      }
    }
    var yy = D.getFullYear();
    var mm = D.getMonth() + 1;
    var dd = D.getDate();
    var ww = D.getDay();
    var ss = parseInt(D.getTime() / 1000);
    if (yy < 100) yy = "19" + yy;
    return GetLunarDay(yy, mm, dd);
  };
  CalendarHelper.GetAddDay = function (D, v) {
    var LSTR_ndate = D;
    var LSTR_Year = LSTR_ndate.getYear();
    var LSTR_Month = LSTR_ndate.getMonth();
    var LSTR_Date = LSTR_ndate.getDate();
    //处理
    var uom = new Date(LSTR_Year, LSTR_Month, LSTR_Date);
    uom.setDate(uom.getDate() + v); //取得系统时间的前一天,重点在这里,负数是前几天,正数是后几天
    return uom;
  }
  //是否除夕
  CalendarHelper.IsLastDayBeforeNewYearOfCN = function (D) {
    var strCurrDay = CalendarHelper.GetCNDate(D);
    var strNextDay = CalendarHelper.GetCNDate(CalendarHelper.GetAddDay(D, 1));
    //alert(strCurrDay+","+strNextDay);
    return strCurrDay.split('年')[0] != strNextDay.split('年')[0];
  };
  //是否春节
  CalendarHelper.IsNewYearOfCN = function (D) {
    var strCurrDay = CalendarHelper.GetCNDate(D);
    var strPrevDay = CalendarHelper.GetCNDate(CalendarHelper.GetAddDay(D, -1));
    //alert(strCurrDay+","+strPrevDay);
    return strCurrDay.split('年')[0] != strPrevDay.split('年')[0];
  };
  //------------------- End ----------------------
  var d1 = new Date();
  var d2 = new Date(2013, 1, 9); //注:此处相当于2013年2月9号
  var d3 = new Date(2013, 1, 10);
  var result = GetResult(d1) + GetResult(d2) + GetResult(d3);
  alert(result);
  function GetResult(D) {
    var y = D.getFullYear();
    var m = D.getMonth() + 1;
    var dd = D.getDate();
    var str = y + "年" + m + "月" + dd + "日";
    var isR = CalendarHelper.IsLastDayBeforeNewYearOfCN(D);
    var isN = CalendarHelper.IsNewYearOfCN(D);
    return "日期:"+str+","+ (isR&#63;"是":"不是") + "除夕" + "," + (isN&#63;"是":"不是") + "春节\n\n" ;
  }
</script>
</head>
<body>
</body>
</html>

更多關於jQuery相關內容有興趣的讀者可查看本站專題:《jQuery日期與時間操作技巧總結》、《jQuery拖曳特效與技巧總結》 、《jQuery擴充技巧總結》、《jQuery常見經典特效總結》、《jQuery動畫與特效用法總結》、《jquery選擇器用法總結》及《jQuery常用外掛及用法總結

希望本文所述對大家jQuery程式設計有所幫助。

陳述:
本文內容由網友自願投稿,版權歸原作者所有。本站不承擔相應的法律責任。如發現涉嫌抄襲或侵權的內容,請聯絡admin@php.cn