本帖最后由 u011669689 于 2013-09-25 18:25:00 编辑
基础条件:
user表 userid ,username
user_money 表 u_id,user_money
user_money_exchange 表:money ,username,ordertag =1或2
现在想执行:
update user_money set user_money = (user_money_exchange 当ordertag =1的 sum(money) + 当ordertag =2的 sum(money)) where user_money.u_id = user.userid
<br />
update user_money <br />
set user_money.money = <br />
<br />
(select sum(ume.money) as m , u.userid from user_money_exchange ume left join user u on ume.username = u.username where ume.ordertag = 1 group by ume.username<br />
+ <br />
select sum(ume.money) as m , u.userid from user_money_exchange ume left join user u on ume.username = u.username where ume.ordertag = 2 group by ume.username) <br />
<br />
where user_money.u_id = u.userid<br />
<br />
这个是错的,想知道对的是?谢谢各位了