ajax 取值,该如何处理

ajax 取值

 <br /> $.ajax({<br />   type: "post",   <br />   url: "ddd.php",   <br />   data: {"inserted":[{"productionName":"空压机","product":"科兴","productionType":"KX-11D","fenjieselect":"分解","proctionNO":"02"},{"productionName":"空压机","product":"科兴","productionType":"KX-12D","fenjieselect":"分解","proctionNO":"03"}],"updated":[],"deleted":[]},   <br />   datatype: "text",<br />   success:function(data){<br />    alert (data);<br /><br /> } <br /><br />})  

我在后台的PHP里如何取到inserted ,updated ,deleted 的值啊？
------解决方案--------------------
你不是写了POST接收吗？ 在ddd.php 里面print_r($_POST)
------解决方案--------------------

<?php<br />if($_POST) {<br />  print_r($_POST);<br />  exit;<br />}<br />?><br /><script src='http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js'></script><br /><script><br />$(function() {<br />  $.ajax({<br />    type: "post",   <br />//   url: "ddd.php",   <br />    data: {"inserted":[{"productionName":"空压机","product":"科兴","productionType":"KX-11D","fenjieselect":"分解","proctionNO":"02"},{"productionName":"空压机","product":"科兴","productionType":"KX-12D","fenjieselect":"分解","proctionNO":"03"}],"updated":[],"deleted":[]},   <br />    datatype: "text",<br />    success:function(data){<br />      alert (data);<br />    }<br />  });<br />});<br /></script><br />