php总是报错，大家帮小弟我看下代码

php总是报错，大家帮我看下代码

if (!function_exists("GetSQLValueString")) {
function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") 
{
  if (PHP_VERSION   $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue;
  }

  $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue);

  switch ($theType) {
  case "text":
  $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
  break;  
  case "long":
  case "int":
  $theValue = ($theValue != "") ? intval($theValue) : "NULL";
  break;
  case "double":
  $theValue = ($theValue != "") ? doubleval($theValue) : "NULL";
  break;
  case "date":
  $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
  break;
  case "defined":
  $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue;
  break;
  }
  return $theValue;
}
}

mysql_select_db($database_test, $test);
$query_test = "SELECT * FROM test";
$test = mysql_query($query_test, $test) or die(mysql_error());
$row_test = mysql_fetch_assoc($test);
$totalRows_test = mysql_num_rows($test);
?>

 

  id
 
 

 

  name
 
 

 

  pass
 
 

 

 
 

 

 
 
 
 
 
  $result1 = mysql_query("SELECT * FROM test where id   while($row1=mysql_fetch_array($result1))
  {
$id=trim($row1[id]);
$name=trim($row1[name]);
$pass=trim($row1[pass]);
  echo
  "
 

 
 
 
  ";
  }
  
  ?>

id	name	pass
$id	$name	$pass

 

mysql_free_result($test);
?>[code=PHP][/code]
=============================
报错：
Notice: Use of undefined constant id - assumed 'id' in D:\xampp\htdocs\vest\index.php on line 68

Notice: Use of undefined constant name - assumed 'name' in D:\xampp\htdocs\vest\index.php on line 69

Notice: Use of undefined constant pass - assumed 'pass' in D:\xampp\htdocs\vest\index.php on line 70

68、69、70这三行是