檢索最近 7 天的交易並在 MySQL 單表中包含空行
解決提取最近 7 天交易的挑戰並從 MySQL資料庫擷取空行,我們將遍歷以下內容方法:
-
產生日期範圍:
我們首先使用以下查詢建立過去7 天的日期清單:select DATE_FORMAT(a.Date,'%Y-%m-%d') as purchase_date, '0' as amount from ( select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY as Date from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c ) a where a.Date BETWEEN NOW() - INTERVAL 7 DAY AND NOW()
-
加入交易表:
接下來,我們將產生的日期清單與交易表連接起來,取得對應的銷售額(如果有):SELECT t1.purchase_date, coalesce(SUM(t1.amount+t2.amount), 0) AS amount from
( select DATE_FORMAT(a.Date,'%Y-%m-%d') as purchase_date, '0' as amount from ( select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY as Date from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c ) a where a.Date BETWEEN NOW() - INTERVAL 7 DAY AND NOW() )t1 left join
( SELECT DATE_FORMAT(purchase_date, '%Y-%m-%d') as purchase_date, coalesce(SUM(amount), 0) AS amount FROM transactions WHERE purchase_date BETWEEN NOW() - INTERVAL 7 DAY AND NOW() AND vendor_id = 0 GROUP BY purchase_date )t2 on t2.purchase_date = t1.purchase_date group by t1.purchase_date order by t1.purchase_date desc
完整查詢:
select t1.purchase_date, coalesce(SUM(t1.amount+t2.amount), 0) AS amount from ( select DATE_FORMAT(a.Date,'%Y-%m-%d') as purchase_date, '0' as amount from ( select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY as Date from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c ) a where a.Date BETWEEN NOW() - INTERVAL 7 DAY AND NOW() )t1 left join ( SELECT DATE_FORMAT(purchase_date, '%Y-%m-%d') as purchase_date, coalesce(SUM(amount), 0) AS amount FROM transactions WHERE purchase_date BETWEEN NOW() - INTERVAL 7 DAY AND NOW() AND vendor_id = 0 GROUP BY purchase_date )t2 on t2.purchase_date = t1.purchase_date group by t1.purchase_date order by t1.purchase_date desc
利用此綜合查詢,我們可以提取過去 7 天每一天的總銷售額,有效地包括沒有交易的日子的空行。
以上是如何檢索單一 MySQL 表中包含空白行的最近 7 天的交易?的詳細內容。更多資訊請關注PHP中文網其他相關文章!

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