。嘶嘶聲

問題

https://leetcode.com/problems/fizz-buzz/description/

解決方案01

class Solution {
    public List<String> fizzBuzz(int n) {

        List<String> ans = new ArrayList<>(n);

        for (int i = 1; i <= n; i++) {

            String text = "";

            if (i % 3 == 0 && i % 5 == 0) {
                text += "FizzBuzz";

                System.out.print("FizzBuzz");
            } else if (i % 3 == 0) {
                text += "Fizz";
                System.out.print("Fizz");
            } else if (i % 5 == 0) {
                text += "Buzz";

                System.out.print("Buzz");
            } else {
                text += String.valueOf(i);
                System.out.print(i);
            }

            ans.add(text);
        };
        return ans;
    }
}

解決方案02

class Solution {
public List<String> fizzBuzz (int n) {

List<String> answer = new ArrayList<>(n);

for (int i = 1; i <= n; i++) {

boolean divisibleBy3 = 1 % 3 == 0;
boolean divisibleBy5 = 1 % 5 == 0;

if (divisibleBy3 && divisibleBy5){

 answer.add("FizzBuzz");

} else if (divisibleBy3) {

 answer.add("Fizz");

} else if (divisibleBy5) { 

answer.add("Buzz");

} else {

answer.add(String.valueOf(i)); }
}
            return answer;
}
}

以上是。嘶嘶聲的詳細內容。更多資訊請關注PHP中文網其他相關文章！