處理具有相同列和索引的多個資料幀時,可能需要建立集群堆積條形圖以視覺化資料。當您想要分別堆疊每個資料幀的長條圖並按對應的索引分組時,就會出現挑戰。
結合使用 Pandas 和 Matplotlib,我們可以實現這一目標透過手動調整條形矩形的位置和陰影圖案。以下是詳細的解決方案:
<code class="python">import pandas as pd import numpy as np import matplotlib.pyplot as plt def plot_clustered_stacked(dfall, labels=None, title="multiple stacked bar plot", H="/" , **kwargs): n_df = len(dfall) n_col = len(dfall[0].columns) n_ind = len(dfall[0].index) axe = plt.subplot(111) for df in dfall: # for each data frame axe = df.plot(kind="bar", linewidth=0, stacked=True, ax=axe, legend=False, grid=False, **kwargs) # make bar plots h, l = axe.get_legend_handles_labels() # get the handles we want to modify for i in range(0, n_df * n_col, n_col): # len(h) = n_col * n_df for j, pa in enumerate(h[i:i+n_col]): for rect in pa.patches: # for each index rect.set_x(rect.get_x() + 1 / float(n_df + 1) * i / float(n_col)) rect.set_hatch(H * int(i / n_col)) #edited part rect.set_width(1 / float(n_df + 1)) axe.set_xticks((np.arange(0, 2 * n_ind, 2) + 1 / float(n_df + 1)) / 2.) axe.set_xticklabels(df.index, rotation = 0) axe.set_title(title) # Add invisible data to add another legend n=[] for i in range(n_df): n.append(axe.bar(0, 0, color="gray", hatch=H * i)) l1 = axe.legend(h[:n_col], l[:n_col], loc=[1.01, 0.5]) if labels is not None: l2 = plt.legend(n, labels, loc=[1.01, 0.1]) axe.add_artist(l1) return axe</code>
使用Seaborn 的barplot 函數,我們可以建立堆疊長條圖,但無法原生堆疊不同資料幀的條形圖。為了克服這個問題,我們可以使用以下解決方法:
<code class="python">import seaborn as sns # Convert dataframes to tidy format dfall.set_index(["Name", "index", "variable"], inplace=1) dfall["vcs"] = dfall.groupby(level=["Name", "index"]).cumsum() dfall.reset_index(inplace=True) # Create color palette c = ["blue", "purple", "red", "green", "pink"] # Iterate through groups and plot stacked bars for i, g in enumerate(dfall.groupby("variable")): ax = sns.barplot(data=g[1], x="index", y="vcs",</code>
以上是如何在 Python 中為多個 DataFrame 建立叢集堆積長條圖?的詳細內容。更多資訊請關注PHP中文網其他相關文章!