搜尋
首頁Javajava教程用 Java 建立旋轉排序數組搜尋:了解樞軸搜尋和二分搜尋

Building a Rotated Sorted Array Search in Java: Understanding Pivot and Binary Search

What is a Rotated Sorted Array?

Consider a sorted array, for example:

[1, 2, 3, 4, 5, 6]

Now, if this array is rotated at some pivot, say at index 3, it would become:

[4, 5, 6, 1, 2, 3]

Notice that the array is still sorted, but it is divided into two parts. Our goal is to search for a target value in such arrays efficiently.


The Search Strategy

To search in a rotated sorted array, we need to:

  1. Find the Pivot: The pivot is the point where the array transitions from larger to smaller values.
  2. Binary Search: Once we find the pivot, we can use binary search on the appropriate half of the array.

Step-by-Step Code Explanation

class Solution {
    public static void main(String[] args) {
        int[] arr = {4, 5, 6, 1, 2, 3}; // Example of rotated sorted array
        int target = 5;

        // Searching for the target
        int result = search(arr, target);

        // Displaying the result
        System.out.println("Index of target: " + result);
    }

    // Main search function to find the target in a rotated sorted array
    public static int search(int[] nums, int target) {
        // Step 1: Find the pivot
        int pivot = searchPivot(nums);

        // Step 2: If no pivot, perform regular binary search
        if (pivot == -1) {
            return binarySearch(nums, target, 0, nums.length - 1);
        }

        // Step 3: If the target is at the pivot, return the pivot index
        if (nums[pivot] == target) {
            return pivot;
        }

        // Step 4: Decide which half of the array to search
        if (target >= nums[0]) {
            return binarySearch(nums, target, 0, pivot - 1); // Search left side
        } else {
            return binarySearch(nums, target, pivot + 1, nums.length - 1); // Search right side
        }
    }

    // Binary search helper function
    static int binarySearch(int[] arr, int target, int start, int end) {
        while (start  arr[mid + 1]) {
                return mid;
            }

            // Check if the pivot is before the mid
            if (mid > start && arr[mid] 




<hr>

<h3>
  
  
  Explanation of the Code
</h3>

<ol>
<li>
<p><strong>search()</strong>:</p>

<ul>
<li>This function is responsible for searching for the target in the rotated sorted array.</li>
<li>First, we find the <strong>pivot</strong> using the searchPivot() function.</li>
<li>Depending on the pivot's position, we then decide which half of the array to search using binary search.</li>
</ul>
</li>
<li>
<p><strong>binarySearch()</strong>:</p>

<ul>
<li>A standard binary search algorithm to find the target in a sorted sub-array.</li>
<li>We define the start and end indices and progressively narrow the search space.</li>
</ul>
</li>
<li>
<p><strong>searchPivot()</strong>:</p>

<ul>
<li>This function identifies the pivot point (the place where the array rotates).</li>
<li>The pivot is the index where the sorted order is "broken" (i.e., the array goes from a higher value to a lower value).</li>
<li>If no pivot is found, it means the array was not rotated, and we can perform a regular binary search.</li>
</ul>
</li>
</ol>


<hr>

<h3>
  
  
  How the Algorithm Works
</h3>

<p>For an array like [4, 5, 6, 1, 2, 3]:</p>

  • The pivot is at index 2 (6 is the largest, and it is followed by 1, the smallest).
  • We use this pivot to divide the array into two parts: [4, 5, 6] and [1, 2, 3].
  • If the target is greater than or equal to the first element (4 in this case), we search the left half. Otherwise, we search the right half.

This method ensures that we search efficiently, achieving a time complexity of O(log n), similar to a standard binary search.


Conclusion

Rotated sorted arrays are a common interview question and a useful challenge to deepen your understanding of binary search. By finding the pivot and adapting our binary search accordingly, we can efficiently search through the array in logarithmic time.

If you found this article helpful, feel free to connect with me on LinkedIn or share your thoughts in the comments! Happy coding!

以上是用 Java 建立旋轉排序數組搜尋:了解樞軸搜尋和二分搜尋的詳細內容。更多資訊請關注PHP中文網其他相關文章!

陳述
本文內容由網友自願投稿,版權歸原作者所有。本站不承擔相應的法律責任。如發現涉嫌抄襲或侵權的內容,請聯絡admin@php.cn
Java平台獨立性:OS之間的差異Java平台獨立性:OS之間的差異May 16, 2025 am 12:18 AM

Java在不同操作系統上的表現存在細微差異。 1)JVM實現不同,如HotSpot、OpenJDK,影響性能和垃圾回收。 2)文件系統結構和路徑分隔符不同,需使用Java標準庫處理。 3)網絡協議實現差異影響網絡性能。 4)GUI組件外觀和行為在不同系統上有別。通過使用標準庫和虛擬機測試,可減少這些差異的影響,確保Java程序穩定運行。

Java的最佳功能:從面向對象的編程到安全性Java的最佳功能:從面向對象的編程到安全性May 16, 2025 am 12:15 AM

javaoffersrobustobject-IentiendedProgrammming(OOP)和Top-Notchsecurityfeatures.1)OopinjavainCludesClasses,對象,繼承,多態性,和列出,andeclingfleximaintainablesys.ss.2)SecurityFeateTuersLudEtersludEterMachine(

JavaScript與Java的最佳功能JavaScript與Java的最佳功能May 16, 2025 am 12:13 AM

JavaScriptandJavahavedistinctstrengths:JavaScriptexcelsindynamictypingandasynchronousprogramming,whileJavaisrobustwithstrongOOPandtyping.1)JavaScript'sdynamicnatureallowsforrapiddevelopmentandprototyping,withasync/awaitfornon-blockingI/O.2)Java'sOOPf

Java平台獨立性:收益,限制和實施Java平台獨立性:收益,限制和實施May 16, 2025 am 12:12 AM

JAVAACHIEVESPLATFORMINDEPENTENCETHROUGHJAVAVIRTAILMACHINE(JVM)和BYTECODE.1)THEJVMINTERPRETSBBYTECODE,允許theingthesmecodetorunonanyanyanyanyplatformwithajvm.2)

Java:真實詞的平台獨立性Java:真實詞的平台獨立性May 16, 2025 am 12:07 AM

java'splatformendependecemeansapplicationscanrunonanyplatformwithajvm,使“ Writeonce,runanywhere”。

JVM性能與其他語言JVM性能與其他語言May 14, 2025 am 12:16 AM

JVM'SperformanceIsCompetitiveWithOtherRuntimes,operingabalanceOfspeed,安全性和生產性。 1)JVMUSESJITCOMPILATIONFORDYNAMICOPTIMIZAIZATIONS.2)c提供NativePernativePerformanceButlanceButlactsjvm'ssafetyFeatures.3)

Java平台獨立性:使用示例Java平台獨立性:使用示例May 14, 2025 am 12:14 AM

JavaachievesPlatFormIndependencEthroughTheJavavIrtualMachine(JVM),允許CodeTorunonAnyPlatFormWithAjvm.1)codeisscompiledIntobytecode,notmachine-specificodificcode.2)bytecodeisisteredbytheybytheybytheybythejvm,enablingcross-platerssectectectectectross-eenablingcrossectectectectectection.2)

JVM架構:深入研究Java虛擬機JVM架構:深入研究Java虛擬機May 14, 2025 am 12:12 AM

TheJVMisanabstractcomputingmachinecrucialforrunningJavaprogramsduetoitsplatform-independentarchitecture.Itincludes:1)ClassLoaderforloadingclasses,2)RuntimeDataAreafordatastorage,3)ExecutionEnginewithInterpreter,JITCompiler,andGarbageCollectorforbytec

See all articles

熱AI工具

Undresser.AI Undress

Undresser.AI Undress

人工智慧驅動的應用程序,用於創建逼真的裸體照片

AI Clothes Remover

AI Clothes Remover

用於從照片中去除衣服的線上人工智慧工具。

Undress AI Tool

Undress AI Tool

免費脫衣圖片

Clothoff.io

Clothoff.io

AI脫衣器

Video Face Swap

Video Face Swap

使用我們完全免費的人工智慧換臉工具,輕鬆在任何影片中換臉!

熱門文章

北端:融合系統,解釋
1 個月前By尊渡假赌尊渡假赌尊渡假赌
Mandragora:巫婆樹的耳語 - 如何解鎖抓鉤
4 週前By尊渡假赌尊渡假赌尊渡假赌
<🎜>掩蓋:探險33-如何獲得完美的色度催化劑
2 週前By尊渡假赌尊渡假赌尊渡假赌

熱工具

EditPlus 中文破解版

EditPlus 中文破解版

體積小,語法高亮,不支援程式碼提示功能

SublimeText3 Mac版

SublimeText3 Mac版

神級程式碼編輯軟體(SublimeText3)

SublimeText3 英文版

SublimeText3 英文版

推薦:為Win版本,支援程式碼提示!

禪工作室 13.0.1

禪工作室 13.0.1

強大的PHP整合開發環境

SublimeText3漢化版

SublimeText3漢化版

中文版,非常好用