PHP获得跳转的真实地址实例

现在有很多的短网址应用，点击就跳转到缩短之前的网址了，那今天我们就来看一下，PHP如何获取短网址跳转之前的网址，其实也很简单，就是用php的get_headers 函数，

取得Response Headers，之后慢慢分析就行了。

给出具体实现方法：

代码如下	复制代码
$header = get_headers($url, 1); if (strpos($header[0], ’301′) || strpos($header[0], ’302′)) { if (is_array($header['Location'])) { return $header['Location'][count($header['Location'])-1]; } else { return $header['Location']; } } else { return $url; }

实例二

代码如下

复制代码

// echo get_redirect_url('http://www.111cN.nEt'); //输出结果为：http://code.google.com/android/ function get_redirect_url($url){     $redirect_url = null;     $url_parts = @parse_url($url);     if (!$url_parts) return false;     if (!isset($url_parts['host'])) return false; //can't process relative URLs     if (!isset($url_parts['path'])) $url_parts['path'] = '/';     $sock = fsockopen($url_parts['host'], (isset($url_parts['port']) ? (int)$url_parts['port'] : 80), $errno, $errstr, 30);     if (!$sock) return false;     $request = "HEAD " . $url_parts['path'] . (isset($url_parts['query']) ? '?'.$url_parts['query'] : '') . " HTTP/1.1rn";     $request .= 'Host: ' . $url_parts['host'] . "rn";     $request .= "Connection: Closernrn";     fwrite($sock, $request);     $response = '';     while(!feof($sock)) $response .= fread($sock, 8192);     fclose($sock);     if (preg_match('/^Location: (.+?)$/m', $response, $matches)){         if ( substr($matches[1], 0, 1) == "/" )             return $url_parts['scheme'] . "://" . $url_parts['host'] . trim($matches[1]);         else             return trim($matches[1]);     } else {         return false;     } }