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Python实现读取目录所有文件的文件名并保存到txt文件代码

WBOY
WBOY原創
2016-06-10 15:18:471307瀏覽

代码: (使用os.listdir)

复制代码 代码如下:

import os

def ListFilesToTxt(dir,file,wildcard,recursion):
    exts = wildcard.split(" ")
    files = os.listdir(dir)
    for name in files:
        fullname=os.path.join(dir,name)
        if(os.path.isdir(fullname) & recursion):
            ListFilesToTxt(fullname,file,wildcard,recursion)
        else:
            for ext in exts:
                if(name.endswith(ext)):
                    file.write(name + "\n")
                    break

def Test():
  dir="J:\\1"
  outfile="binaries.txt"
  wildcard = ".txt .exe .dll .lib"
 
  file = open(outfile,"w")
  if not file:
    print ("cannot open the file %s for writing" % outfile)

  ListFilesToTxt(dir,file,wildcard, 1)
 
  file.close()

Test()

代码:(使用os.walk) walk递归地对目录及子目录处理,每次返回的三项分别为:当前递归的目录,当前递归的目录下的所有子目录,当前递归的目录下的所有文件。

复制代码 代码如下:

import os

def ListFilesToTxt(dir,file,wildcard,recursion):
    exts = wildcard.split(" ")
    for root, subdirs, files in os.walk(dir):
        for name in files:
            for ext in exts:
                if(name.endswith(ext)):
                    file.write(name + "\n")
                    break
        if(not recursion):
            break

def Test():
  dir="J:\\1"
  outfile="binaries.txt"
  wildcard = ".txt .exe .dll .lib"
 
  file = open(outfile,"w")
  if not file:
    print ("cannot open the file %s for writing" % outfile)

  ListFilesToTxt(dir,file,wildcard, 0)
 
  file.close()

Test()

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