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生产上数据库大量的latchfree导致的CPU资源耗尽的问题的解决

WBOY
WBOY原創
2016-06-07 16:06:471808瀏覽

中午的时候,我们生产上的某个数据库,cpu一直居高不下 通过如下的sql语句,我们查看当时数据库的等待,争用的情况: select s.SID, s.SERIAL#, kill -9 || p.SPID, s.MACHINE, s.OSUSER, s.PROGRAM, s.USERNAME, s.last_call_et, a.SQL_ID, s.LOGON_TIME, a

中午的时候,我们生产上的某个数据库,cpu一直居高不下

\

通过如下的sql语句,我们查看当时数据库的等待,争用的情况:

select s.SID,
       s.SERIAL#,
       'kill -9 ' || p.SPID,
       s.MACHINE,
       s.OSUSER,
       s.PROGRAM,
       s.USERNAME,
       s.last_call_et,
       a.SQL_ID,
       s.LOGON_TIME,
       a.SQL_TEXT,
       a.SQL_FULLTEXT,
       w.EVENT,
       a.DISK_READS,
       a.BUFFER_GETS
  from v$process p, v$session s, v$sqlarea a, v$session_wait w
 where p.ADDR = s.PADDR
   and s.SQL_ID = a.sql_id
   and s.sid = w.SID
   and s.STATUS = 'ACTIVE'
 order by s.last_call_et desc;

从event可以看到,是latch 的争用导致的原因

\

通过如果的sql,查看是什么样的latch

select * from v$session_wait 
where event  like 'latch free';
 

\

P2就是 这个latch的name,通过v$latchname这个视图就可以知道哪个具体的latch

1:45:55 PM SQL> select * from v$latchname where latch#=164;
 
    LATCH# NAME                                                                   HASH
---------- ---------------------------------------------------------------- ----------
       164 simulator hash latch                                             2233208730


查看latch的历史情况

2:11:59 PM SQL> select name,gets,misses,sleeps from v$latch where sleeps >0 order by sleeps desc;
 
NAME                                                                   GETS     MISSES     SLEEPS
---------------------------------------------------------------- ---------- ---------- ----------
simulator hash latch                                             4827860212  135426899   10890947
cache buffers chains                                             1619822817 2850976006    4747728
gc element                                                       4660052091   25748270     175073
resmgr:schema config                                               91872524     153968      95708
ges resource hash list                                            174151449    1070556      55459
Real-time plan statistics latch                                    40953155     651496      44527
call allocation                                                     3301878     265908      43501
row cache objects                                                 336300485    4970324      19366


这个simulator hash latch已经是显著的latch部分

eagle在他的网站上有篇文章讲到了关于simulator这个

http://www.eygle.com/archives/2011/11/simulator_lru_latch.html

simulator意为模拟,也就是说当Oracle在内存中进行数据块处理时,实际上还会在预先分配的Buffer中进行相关信息记录,如DBA信息,当数据块被老化之后,下次读取时,如果请求的数据在Simulator内存中存在,则认为继续缓存该数据块是有意义的,通过监控并模拟统计这些操作,并对计算结果加权运算,就可以实现对于内存的调整建议。
在模拟过程中,也是通过Latch来实现的,相关的Latch就有 simulator lru latch 、 simulator hash latch等.

就Buffer Cache而言,如果系统中该类争用严重,则可以考虑关闭db_cache_advice,消除这部分内部操作对于性能的影响。
以下是一个相关BUG,在该Bug中,由于DB_CACHE_ADVICE的开启导致了严重的simulator lru latch的竞争:

Bug 5918642 Heavy latch contention with DB_CACHE_ADVICE on

This note gives a brief overview of bug 5918642.
The content was last updated on: 01-APR-2008
Click here for details of each of the sections below.

Affects:

Product (Component) Oracle Server (Rdbms)
Range of versions believed to be affected Versions
Versions confirmed as being affected
  • 10.2.0.3
Platforms affected Generic (all / most platforms affected)

Fixed:

This issue is fixed in
  • 11.2 (Future Release)
  • 10.2.0.4 (Server Patch Set)
  • 11.1.0.7 (Server Patch Set)

Symptoms:

Related To:

  • Latch Contention
  • Waits for "latch free"
  • Performance Monitoring
  • DB_CACHE_ADVICE

Description

High simulator lru latch contention can occur when db_cache_advice is
set to ON if there is a large buffer cache.


Workaround:
  Set db_cache_advice to OFF

当然,这个只是治标不治本的做法,这个是显现的表象的问题,根源的问题还是这个sql语句有问题

当一个数据块读入到sga中时,该块的块头(buffer header)会放置在一个hash bucket的链表(hash chain)中。该内存结构由一系列cache buffers chains子latch保护(又名hash latch或者cbc latch)。对Buffer cache中的块,要select或者update、insert,delete等,都得先获得cache buffers chains子latch,以保证对chain的排他访问。若在过程中发生争用,就会等待latch:cache buffers chains事件。

产生原因: 1. 低效率的SQL语句(主要体现在逻辑读过高) 在某些环境中,应用程序打开执行相同的低效率SQL语句的多个并发会话,这些SQL语句都设法得到相同的数据集,每次执行都带有高 BUFFER_GETS(逻辑读取)的SQL语句是主要的原因。相反,较小的逻辑读意味着较少的latch get操作,从而减少锁存器争用并改善性能。注意v$sql中BUFFER_GETS/EXECUTIONS大的语句。 2.Hot block 当多个会话重复访问一个或多个由同一个子cache buffers chains锁存器保护的块时,热块就会产生。当多个会话争用cache buffers chains子锁存器时,就会出现这个等待事件。有时就算调优了SQL,但多个会话同时执行此SQL,那怕只是扫描特定少数块,也是也会出现HOT BLOCK的。

SELECT P935.SEQUENCEID,
       null FA_SEQUENCEID,
       P935.ORDERID,
       P935.ORGORDERID,
       P935.PRODUCTNAME,
       P935.PRODUCTNUM,
       P935.ORDERTIME,
       P935.LASTUPDATETIME,
       P935.ORDERSTATUS,
       P935.MEMO,
       935 orderCode,
       P935.PAYERACCTCODE,
       P935.PAYERACCTTYPE,
       P935.PAYEEACCTCODE PLATACCTCODE,
       P935.PAYEEACCTTYPE PLATACCTTYPE,
       P936.PAYEEACCTCODE,
       P936.PAYEEACCTTYPE,
       EXT935.PAYER_DISPLAYNAME,
       EXT935.PAYER_NAME,
       EXT935.PAYER_IDC,
       EXT935.PAYER_MEMBERTYPE,
       EXT936.PAYER_DISPLAYNAME PLAT_DISPLAYNAME,
       EXT936.SUBMITNAME PLAT_NAME,
       EXT936.PAYER_IDC PLAT_IDC,
       EXT936.PAYER_MEMBERTYPE PLAT_MEMBERTYPE,
       EXT936.PAYEE_DISPLAYNAME,
       EXT936.PAYEE_NAME,
       EXT936.PAYEE_IDC,
       EXT936.PAYEE_MEMBERTYPE,
       P935.PAYEEDISPLAYNAME WEBSITENAME,
       CASE
         WHEN (SELECT count(*)
                 FROM PAYMENTORDER P936
                WHERE P936.Ordercode = 936
                  and P936.Orderstatus = 0
                  AND <span style="color:#ff0000;">P936.Relatedsequenceid = P935.SEQUENCEID</span>) > 0 THEN
          0
         ELSE
          1
       END AS SHARINGRESULT,
       CASE D935.Dealcode
         WHEN 210 then
          14
         else
          D935.DEALTYPE
       end PAYMETHOD,
       D935.DEALAMOUNT,
       G935.EXT1,
       G935.Ext2,
       G935.PAYERCONTACTTYPE,
       G935.PAYERCONTACT,
       NVL(D935.PAYEEFEE, 0) PAYEEFEE,
       NVL(D935.PAYERFEE, 0) PAYERFEE,
       nvl(MS936.PAYEEFEE, 0) PLATFORMFEE,
       P935.VERSION
  FROM PAYMENTORDER          P935,
       PAYMENTORDER          P936,
       DEAL                  D935,
       GATEWAYORDER          G935,
       MSGATEWAYSHARINGORDER MS936,
       PAYMENTORDEREXT       EXT935,
       PAYMENTORDEREXT       EXT936
 WHERE P936.ORDERCODE = 936
   AND P935.ORDERCODE = 935
   AND P936.RELATEDSEQUENCEID = to_char(P935.SEQUENCEID)
   AND P935.SEQUENCEID = G935.SEQUENCEID(+)
   AND P935.SEQUENCEID = D935.ORDERSEQID(+)
   AND P935.SEQUENCEID = EXT935.ORDERSEQID(+)
   AND P936.SEQUENCEID = EXT936.ORDERSEQID(+)
   AND P936.SEQUENCEID = MS936.SEQUENCEID(+)
   AND MS936.SHARINGTYPE = 1
   AND P935.SEQUENCEID = :1
UNION
SELECT P938.SEQUENCEID,
       P935.SEQUENCEID FA_SEQUENCEID,
       P938.ORDERID,
       P938.ORGORDERID,
       P935.PRODUCTNAME,
       P935.PRODUCTNUM,
       P938.ORDERTIME,
       P938.LASTUPDATETIME,
       P938.ORDERSTATUS,
       P938.MEMO,
       938 orderCode,
       P938.PAYERACCTCODE,
       P938.PAYERACCTTYPE,
       P938.PAYEEACCTCODE PLATACCTCODE,
       P938.PAYEEACCTTYPE PLATACCTTYPE,
       P938.PAYEEACCTCODE,
       P938.PAYEEACCTTYPE,
       EXT938.PAYER_DISPLAYNAME,
       EXT938.PAYER_NAME,
       EXT938.PAYER_IDC,
       EXT938.PAYER_MEMBERTYPE,
       EXT938.PAYEE_DISPLAYNAME PLAT_DISPLAYNAME,
       EXT938.SUBMITNAME PLAT_NAME,
       EXT938.PAYEE_IDC PLAT_IDC,
       EXT938.PAYEE_MEMBERTYPE PLAT_MEMBERTYPE,
       EXT938.PAYEE_DISPLAYNAME,
       EXT938.PAYEE_NAME,
       EXT938.PAYEE_IDC,
       EXT938.PAYEE_MEMBERTYPE,
       P935.PAYEEDISPLAYNAME WEBSITENAME,
       null SHARINGRESULT,
       D938.DEALTYPE PAYMETHOD,
       D938.DEALAMOUNT,
       G935.EXT1,
       G935.Ext2,
       G935.PAYERCONTACTTYPE,
       G935.PAYERCONTACT,
       NVL(D938.PAYEEFEE, 0) PAYEEFEE,
       NVL(D938.PAYERFEE, 0) PAYERFEE,
       0 PLATFORMFEE,
       P935.VERSION
  FROM PAYMENTORDER    P935,
       PAYMENTORDER    P938,
       DEAL            D938,
       GATEWAYORDER    G935,
       PAYMENTORDEREXT EXT938
 WHERE P935.ORDERCODE = 935
   AND P938.ORDERCODE = 938
   AND P938.RELATEDSEQUENCEID = to_char(P935.SEQUENCEID)
   AND P935.SEQUENCEID = G935.SEQUENCEID(+)
   AND P938.SEQUENCEID = D938.ORDERSEQID(+)
   AND P938.SEQUENCEID = EXT938.ORDERSEQID(+)
   AND P935.SEQUENCEID = :2

分析上面的sql,上面标红的地方,等号左边是varchar2的数据类型,括号右边是number的数据类型,会导致数据类型的隐式转换,造成极大的性能影响

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