angular.js - 关于 angularjs 的 ng-options 指令

Question

我通过 ajax 在控制器中拉取到一个数组，var fruits = ['apple', 'banana']，希望实现的是如下效果：

<select>
  <option value='apple'>苹果</option>
  <option value='banana'>香蕉</option>
</select>

<select ng-options="fruit for fruit in fruits">
</select>

得到了

<select ng-options="fruit for fruit in fruits">
  <option value="0" selected="selected" label="apple">apple</option>
  <option value="1" selected="selected" label="apple">banana</option>
</select>

应该怎么通过修改 ng-options 标签来修改 value 的值呢？

Answer 1

Just use ng-repeat option...

In fact, there is a solution:
http://stackoverflow.com/questions/12139152/how-to-set-the-value-property-in-angularjs-ng-options

Answer 2

How to change fruit into an object array

Answer 3

var data = {"201":"活动1","202":"活动2","203":"活动3"}  

<select class="form-control" ng-model="activityId" ng-options="id as name for (id, name) in data" ></select>

var toys = [{"id":"11", "name":"玩具1"},{"id":"12", "name":"玩具2"},{"id":"13", "name":"玩具3"}];

<select class="form-control" ng-model="toyId" ng-options="toy.id as toy.title for toy in toys" required></select>