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angular.js - angularjs在link中操作dom的一些考虑?

<li select-all status="checked">全选</li>
<p>
    <input type="checkbox" ng-checked="checked" ng-model="checked">
    <input type="checkbox" ng-checked="checked" ng-model="checked">
    <input type="checkbox" ng-checked="checked" ng-model="checked">
</p>

我在link中可以更改checked并影响视图,实现点击全选的功能,
但是其实我也可以向下面这样

<li select-all boxWrap=".checkbox">全选</li>
<p class="checkbox">
    <input type="checkbox" >
    <input type="checkbox">
    <input type="checkbox">
</p>

然后在directive的link中拿到 .checkbox 然后使用jq先拿到p.checkbox 然后将input[type=checkbox]
一次设置成checked ,反选的时候类似

这种方案我更喜欢第二种,我觉得可能不会产生太多的$watch, 但是我觉得第二种方法 设置类名作为dirctive
的属性好像就是 拐了个弯来使用 jq。
有没有好的建议,或者其他实现方法。

PHP中文网PHP中文网2744 days ago534

reply all(2)I'll reply

  • 为情所困

    为情所困2017-05-15 16:54:09

    The first method is actually very bad, because too much ng-checked will generate a large number of $watchers on the same scope. affect performance.

    You can look at the source code of angular ng-checked for this

    javascript// boolean attrs are evaluated
    forEach(BOOLEAN_ATTR, function(propName, attrName) {
      // binding to multiple is not supported
      if (propName == "multiple") return;
    
      var normalized = directiveNormalize('ng-' + attrName);
      ngAttributeAliasDirectives[normalized] = function() {
        return {
          restrict: 'A',
          priority: 100,
          link: function(scope, element, attr) {
            scope.$watch(attr[normalized], function ngBooleanAttrWatchAction(value) {
              attr.$set(attrName, !!value);
            });
          }
        };
      };
    });
    

    You can see that there are as many $watchers as there are ng-checked. It's definitely not a best practice to do this.

    The second method is really not good as you said (don’t expose the idea of ​​dom operation to the view, it won’t work at all).

    Analyze the demand. In fact, this demand is analyzed into the idea of ​​angular model. It can be like this.

    Select all button -> A

    checkbox1 -> A1
    checkbox2 -> A2
    checkbox3 -> A3
    checkbox4 -> A4

    When the value of A's model is (true value), the values ​​of A1-A4model are changed to (true value); then execution in the instruction triggers the $digest loop. so. Don’t change all checkboxes. This way $watcher will not be generated. And the goal of selecting all was achieved.

    Give you a piece of code written casually:

    html<label checkbox-select-all group="['checkbox1', 'checkbox2', 'checkbox3']">全选</label>
    <p>
        <input type="checkbox" ng-model="checkbox1"> 1
        <input type="checkbox" ng-model="checkbox2"> 2
        <input type="checkbox" ng-model="checkbox3"> 3
    </p>
    
    javascriptdirective('checkboxSelectAll', ['$parse', function($parse){
        var linkFn = function(scope, element, attrs){
    
            var group = $parse(attrs.group || '[]')(scope);
    
            element.on('click', function(){
                scope.$apply(function(){
                    group.forEach(function(checkbox){
                        scope[checkbox] = true;
                    });
                });
            });
    
        };
    
        return {
            restrict: 'A',
            link: linkFn
        }
    
    }])
    

    In this case, the second situation you mentioned will not happen.
    This form has strong scalability. (I can implement it when I have time) It can support category selection. (The above is just random code).

    Actually, I think the questioner’s biggest confusion about this question may be because he is familiar with using DOM operations to solve problems. In fact, I used to be like this too. (I still do this sometimes). Very normal.

    ====================================

    After get off work today, I implemented a draft version based on the envisioned model (implemented casually, lacking two-way binding). Put it on Plunker.
    This version is a rough draft. There are many imperfections, such as ng-true-value, ng-false-value and other functions.

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    0
  • 高洛峰

    高洛峰2017-05-15 16:54:09

    I personally feel that the first method is fine, but using the second method feels a bit complicated.

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    0
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