For example, there is a set of data:
name: 'food',
data: {
fruit: [
{
name: 'apple',
stock: 10
},
{
name: 'pear',
stock: 66
}
...
]
}
db.col.find({'data.fruit.stock': 66}, {data.fruit.stock: 1})
The query is the entire data.fruite
;
Q1: Is there any way to get only the data queried by the filter? What if the document object size is relatively large?
Q2: Is this a feature of Mongodb? After matching the filter condition, is the entire document object returned?
Q3: Is there any API documentation in this area that I can refer to?
怪我咯2017-05-02 09:26:53
The question asked by the questioner is actually related to the trade-off between Data Model and business query.
1. MongoDB returns basically the unit of document each time. If the document contains an array (Array), all arrays need to be returned;
2. As the subject wishes, if you want to follow the query conditions and just return the data in the array that meets the conditions, you can consider
1)重新设计data model,不使用数组嵌套;
2)使用$unwind,将数组按照Flat展开,可以参考下面这个帖子:
/q/10...
For reference.
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漂亮男人2017-05-02 09:26:53
> db.example.find().pretty()
{
"_id" : ObjectId("58b50cd6a7329db9121efa00"),
"name" : "food",
"data" : {
"fruit" : [
{
"name" : "apple",
"stock" : 10
},
{
"name" : "pear",
"stock" : 66
}
]
}
}
> db.example.find({'data.fruit.stock':66}, {'data.fruit.stock': 1}).pretty()
{
"_id" : ObjectId("58b50cd6a7329db9121efa00"),
"data" : {
"fruit" : [
{
"stock" : 10
},
{
"stock" : 66
}
]
}
}
It will indeed return the stock of data.fruit data; but it can also return the stock of conditions, but you need to know the index number of stock in the fruit array.
That’s
{'data.fruit.1.sock': 1}
Reference (mongodb version 3.4):
https://docs.mongodb.com/manu...
https://docs.mongodb.com/manu...