字符串函数 - Ruby 中如何生成一个随机字符串？

Question

需要得到一个大小写混合的字符串[a,A-Z,z]，目前用的方法是

value = ""; 12.times{value << ((rand(2)==1?65:97) + rand(26)).chr}

感觉还是不好，而且再加混合数字的串就不会了。不知道有没有更好的方法，烦请详细指点！

Answer 1

(0...50).map{ ('a'..'z').to_a[rand(26)] }.join

The following is more efficient:
o = [('a'..'z'),('A'..'Z')].map{|i| i.to_a}.flatten;
string = (0...50).map{ o[rand(o.length)] }.join;

Answer 2

Add one more for the poster to choose from:
rand(36 ** n).to_s(36)
n is the length of the generated string

Answer 3

[*('a'..'z'),*('A'..'Z'),*(0..9)].shuffle[0..9].join