search

Home  >  Q&A  >  body text

mongoengine - mongodb如何将每个文档的List类型字段,汇总到一起作为一个整体返回?

如题,mongodb数据库,使用的mongoengine建立的ORM模型,现有一个实体内有一个List类型的字段,如:

class Service(Document):
    ...
    xx = ListField(StringFiled(...))
    ...

现在我想将每个Service文档记录下的xx字段的列表,汇总到一个list,怎么写比较合理呢? 有mongoengine语法更法,没有告诉我pymongo也行,提代个思路,谢谢!

ringa_leeringa_lee2843 days ago654

reply all(1)I'll reply

  • 高洛峰

    高洛峰2017-04-22 09:00:51

    Aggregation Framework (2.2 and later) can easily solve this problem. http://docs.mongodb.org/manual/core/aggregation-introduction/

    We can meet your needs at $group操作中,$push或者$addToSet. Drivers such as pymongo also support Aggregation Framework.

    reply
    0
  • Cancelreply