java - C语言的一道算法题-兄弟郊游问题 求解？
这道题怎么做？？请给大神们解释一下可以吗？
高洛峰2017-04-18 10:58:44
The time a dog runs is the same as the time a human runs
(5x10/(15-10))x20 = 200
PHP中文网2017-04-18 10:58:44
Correct answer to Floor 1 ("Four Seasons"). The key to this question is: time consistency, that is, the time it takes for the dog to run and the time it takes for the brother to catch up with the brother are the same. The formula is: s=Z(MX)/(Y-X), where (M*X)/(Y-X) is the time for the dog to run.