java - 做一个视频播放器，想实现一个功能，如果3秒不点击屏幕任何，则下方一个界面布局（显示按钮那些的）自动消失。

Question

就是这个功能不知道怎么实现，就像很多视频播放器那种，如果点击屏幕任何，下方界面布局（显示按钮那些的）就显示出来，然后等几秒钟没有点击，就消失。
先贴个代码：

 sv.setOnTouchListener(new View.OnTouchListener() {
           @Override
           public boolean onTouch(View v, MotionEvent event) {
               if (linearLayout.getVisibility()==View.INVISIBLE)
                   linearLayout.setVisibility(View.VISIBLE);
              Timer timer=new Timer();
               timer.schedule(new TimerTask() {
                   @Override
                   public void run() {
                       linearLayout.setVisibility(View.VISIBLE);
                   }
               },3000);
               return false;
           }
       });

这种方法不行的，会抛出异常，但是我感觉这个思路没有错，肯定是设置一个surfaceview的触摸事件监听器，但是真的不知道如何实现。以上抛出只有原本的线程能操作ui线程，也就是说主要问题是timer这个线程无法操作setvisibility,但是如果不加入其它线程，又如何实现这个功能，不可能在监听器里面用一个延迟函数，如果在这3秒内又又一次触摸时间，那肯定是要刷新这个时间的啊。。的确没想到解决方法。。。

Answer 1

No need for timer

        Handler mHandler = new Handler();
        Runnable mRunnable;

        mRunnable = new Runnable() {
            @Override
            public void run() {
               //隐藏view
            }
        };
        
        myView.setOnTouchListener(new View.OnTouchListener() {
            @Override
            public boolean onTouch(View v, MotionEvent event) {
                if(event.getAction() == MotionEvent.ACTION_DOWN){
                    mHandler.removeCallbacks(mRunnable);
                    //显示你的view
                }else if(event.getAction() == MotionEvent.ACTION_UP || event.getAction() == MotionEvent.ACTION_CANCEL){
                    mHandler.postDelayed(mRunnable,3000);

                }
                return false;
            }
        });

Answer 2

You are operating the UI thread in a child thread. This is prohibited. Add a handler

       

Handler mHandler = new Handler() {
    @Override
    public void handleMessage(Message msg) {
        super.handleMessage(msg);
        linearLayout.setVisibility(View.VISIBLE);
    }
};
           
timer.schedule(new TimerTask() {
        @Override
        public void run() {
             //linearLayout.setVisibility(View.VISIBLE);
             mHandler.sendEmptyMessage(0);
        }
},3000);

Answer 3

runOnUiThread

Answer 4

Just send a delayed handler to hide the layout. There will be unexpected problems when operating the UI in a child thread.

Answer 5

Try using the Handler.postDelay() method.

Time lastTime;
触摸屏幕
if(View.VISIBLE){
  setVisibility(View.INVISIBLE);
}
  else{
  setVisibility(View.VISIBLE);
  lastTime= new Time();
  Handler.postDelay(3000);
}

Handler.handleMessage{
  if(View.VISIBLE){
  if(new Time()-lastTime>3S){
    setVisibility(View.INVISIBLE);
    }
  }
}

Answer 6

Use directly

new Handler().postDelayed(new Runnable(){
    @Override
    public void run(){
        method()
    }
}, 3000);