java - preparedStatement中怎么样传如 in(?)中的参数

Question

如下面的例子：
？中是一个列表，如'1','2','3'.
替换后应该是 in ('1','2','3'),但是我把'1','2','3'传进取却不能正确的执行取得结果，跟踪发现参数被当初一个字符串了里面的引号被转义了，变成in (''1','2','3'') ,导致结果不对，请问像sql中 in (?)，preparedStatement设置参数要怎么处理？

Answer 1

Just watched it again in javapreparedStatement

should be handled like this:

PreparedStatement statement = connection.prepareStatement("Select * from test where field in (?)");
Array array = statement.getConnection().createArrayOf("VARCHAR", new Object[]{"A1", "B2","C3"});
statement.setArray(1, array);
ResultSet rs = statement.executeQuery();

or:

in(?,?,?)Then assign multiple times

Answer 2

http://fish198398.iteye.com/b...