编码 - Python 3.6中 'utf-8' codec can't decode byte invalid start byte?

Question

Python 3.6中，网页信息解析失败，试了很多种编码，查看网页的编码方式也是utf-8。
错误信息：'utf-8' codec can't decode byte 0x8b in position 1: invalid start byte?
还有就是第一个print终端里打印出来的unicode内容是[b'\x1f\x8b\x08\x00\x...]这种格式的，之前也有过这种情况，一个print打2个变量，就是b'\x, 如果分来2行打又变回了汉字。是因为什么原因呢？

# -*- coding: utf-8 -*-
import json , sqlite3
import urllib.request

url = ('http://wthrcdn.etouch.cn/weather_mini?city=%E4%B8%8A%E6%B5%B7')
resp = urllib.request.urlopen(url)
content = resp.read()

print(content)
print(type(content))
print(content.decode('utf-8'))

Answer 1

After looking at the website, the data returned is gzip compressed data, so it needs to be decoded

# coding=utf-8
from io import BytesIO
import gzip
import urllib.request

url = ('http://wthrcdn.etouch.cn/weather_mini?city=%E4%B8%8A%E6%B5%B7')
resp = urllib.request.urlopen(url)
content = resp.read() # content是压缩过的数据

buff = BytesIO(content) # 把content转为文件对象
f = gzip.GzipFile(fileobj=buff)
res = f.read().decode('utf-8')
print(res)

Answer 2

Isn’t requests easy to use?

Answer 3

It is recommended to use requestet, the code is as follows:

import requests

r = requests.get('http://wthrcdn.etouch.cn/weather_mini?city=%E4%B8%8A%E6%B5%B7')
print(r.text)

Answer 4

It’s not a character encoding problem, just look at the Response headers you requested

    Status Code: 200 OK
    Access-Control-Allow-Headers: *
    Access-Control-Allow-Methods: *
    Access-Control-Allow-Origin: *
    Cache-Control: must-revalidate, max-age=300
    Connection: Keep-Alive
    Content-Encoding: gzip
    Content-Length: 443
    Date: Fri, 10 Mar 2017 03:20:46 GMT
    Fw-Cache-Status: hit
    Fw-Via: HTTP MISS from 58.59.19.99, DISK HIT from 183.131.161.27
    Server: Tengine/2.1.2

It is gzip. If you use the standard library, you need to unzip it