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java - @query注解怎么获取方法参数的某个属性值

PHPzPHPz2765 days ago348

reply all(2)I'll reply

  • 阿神

    阿神2017-04-18 10:15:13

    Similar to this

    @Query("select h from Hotel h where h.city = ?1")
    List<Hotel> queryWorkFormList(City city);

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  • ringa_lee

    ringa_lee2017-04-18 10:15:13

    Example given by Spring:

    @Query("select u from User u where u.firstname = :#{#customer.firstname}")
    List<User> findUsersByCustomersFirstname(@Param("customer") Customer customer);

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