python2.x
跑一段代码的时候,可能会报错某个错误,如果报错了,只需要进行一些处理,然后再继续执行原来的代码就好。
我目前是用try .. except来处理的,但是像这样只要报错就只会执行except下的代码然后程序结束
如果我加上finally的话,我又不能知道具体出错的是哪句代码(每一句都有可能报错),所以也没办法在finally下面加上后续的代码。
怪我咯2017-04-18 09:59:02
What about reducing the granularity of try-catch? Or paste your code for analysis. What you said about continuing to execute the original code after an exception is a bit vague.
【Edit】
After reading the other two answers, they are basically the two ideas I put forward in the comments below. It should be said that everyone’s ideas are basically the same. Modify it here and give me a code plan:
# introduce a new function
# @return: succeed, new_ip
def exec(ip, url):
try:
# do what you want to do
return True, ip
except:
# change your id
return False, new_ip
# your original logics
urls = [url1, url2, ..., url10]
i = 0
ip = ip1
while i <= len(urls):
succeed, ip = exec(ip, urls[i])
if succeed:
i +=1
黄舟2017-04-18 09:59:02
I just wrote one, which is to generate Access Token
的,Access Token
在数据库中是唯一的,但是生成Access Token
的函数不能保证每次生成的Access Token
都是不一样的。所以我用了一个很恶心的while
loop. It’s roughly as follows:
while True:
try:
access_token = make_token()
access_token.add_to_db
break
except IntegrityError as e:
if e.orig.args[0] == 1062:
# 这种情况下,发生了mysql 1062异常,说明数据库中有重复的access token,需要反复生成新的,直至不同
pass
else:
raise e
Not clever, but it works.
Or talk about your business, maybe it doesn’t have to be so disgusting.
Original text of the question: This is a bit more troublesome for me. For example, I need to request 10 URLs in sequence. If the fifth URL is disconnected, an error will be reported, and then I will execute the code below except to change the IP. It is impossible every time Please write a while request, this is simply unreadable
My plan:
def r(uri, data):
while True:
try:
res = requests(uri, data)
return res
except:
change_ip()
This solution should be possible for single-process and single-thread synchronous requests.