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python2.7 - 在python中处理错误时,在执行完except语句下的内容后是否有办法回跳到代码出错的地方继续执行

python2.x

跑一段代码的时候,可能会报错某个错误,如果报错了,只需要进行一些处理,然后再继续执行原来的代码就好。

我目前是用try .. except来处理的,但是像这样只要报错就只会执行except下的代码然后程序结束

如果我加上finally的话,我又不能知道具体出错的是哪句代码(每一句都有可能报错),所以也没办法在finally下面加上后续的代码。

PHPzPHPz2741 days ago1178

reply all(2)I'll reply

  • 怪我咯

    怪我咯2017-04-18 09:59:02

    What about reducing the granularity of try-catch? Or paste your code for analysis. What you said about continuing to execute the original code after an exception is a bit vague.

    【Edit】
    After reading the other two answers, they are basically the two ideas I put forward in the comments below. It should be said that everyone’s ideas are basically the same. Modify it here and give me a code plan:

    # introduce a new function
    # @return: succeed, new_ip
    def exec(ip, url):
        try:
            # do what you want to do 
            return True, ip
        except:
            # change your id
            return False, new_ip
            
    # your original logics
    urls = [url1, url2, ..., url10]
    i = 0
    ip = ip1
    while i <= len(urls):
        succeed, ip = exec(ip, urls[i])
        if succeed:
            i +=1 

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  • 黄舟

    黄舟2017-04-18 09:59:02

    I just wrote one, which is to generate Access Token的,Access Token数据库中是唯一的,但是生成Access Token的函数不能保证每次生成的Access Token都是不一样的。所以我用了一个很恶心的whileloop. It’s roughly as follows:

    while True:
        try:
            access_token = make_token()
            access_token.add_to_db
            break
        except IntegrityError as e:
            if e.orig.args[0] == 1062:
                # 这种情况下,发生了mysql 1062异常,说明数据库中有重复的access token,需要反复生成新的,直至不同
                pass
            else:
                raise e

    Not clever, but it works.

    Or talk about your business, maybe it doesn’t have to be so disgusting.

    Original text of the question: This is a bit more troublesome for me. For example, I need to request 10 URLs in sequence. If the fifth URL is disconnected, an error will be reported, and then I will execute the code below except to change the IP. It is impossible every time Please write a while request, this is simply unreadable

    My plan:

    def r(uri, data):
        while True:
            try:
                res = requests(uri, data)
                return res
            except:
                change_ip()

    This solution should be possible for single-process and single-thread synchronous requests.

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