python - 为什么文件搜索时递归不完全？

Question

import os
#os.chdir('C:\Users\Administrator\Desktop\\TEST')


def search(keyword,pathname):
    for f in os.listdir(pathname):
        if os.path.isfile(f):
            if keyword in f:
                print os.path.join(pathname,f)
        if os.path.isdir(f):
            os.chdir(os.path.join(pathname,f))
            pathname=os.getcwd()
            search(keyword,pathname=os.getcwd())
    

if __name__ == "__main__":
    keyword=raw_input('input:')
    pathname=os.getcwd()
    search(keyword,pathname)

本人欲用递归的方式查询并输出文件名中含有关键词的文件，可是此处代码运行后却只能搜索当前目录下的文件，而符合要求的二级、三级目录内的文件却无法检验出？已修改多次，然问题依旧，请相关爱好者及行业从业者交流、指正，谢谢！

Answer 1

Path problem, please note that the path of the file refers to the complete path, not the string in os.listdir. The corrected procedure is as follows:

import os

def search(keyword,pathname):
    for f in os.listdir(pathname):
        real_path = os.path.join(pathname,f)
        if os.path.isfile(real_path):
            if keyword in f:
               print real_path
        if os.path.isdir(real_path):
            search(keyword,real_path)

if __name__ == "__main__":
    keyword=raw_input('input:')
    pathname=os.getcwd()
    search(keyword,pathname)