python - flask获取URL访问结果

Question

使用flask想实现一个简单的功能，
访问一个类似http://www.baidu.com的URL，然后获取URL的访问结果，展示在页面上，百度未果，新手求教！

Answer 1

Jump directly to the URL you want. Taking other people’s web pages is suspected of infringement. I don’t understand the purpose of this requirement. Want to make a mirror website?

Answer 2

Don’t quite understand what you want to do? If you just want to access a simple web page, you can use urllib or something like that.

Answer 3

1. Write an input box on your page to obtain search keywords
2. Construct Baidu’s search url based on the value of your input
3. Splice urls

Example:
input value = test
The spliced ​​url is as follows:
https://www.baidu.com/s?ie=ut...

Answer 4

It is recommended to install and use the request library

$ pip install requests

from flask import make_response
import requests

@app.route("/test")
def test():
    response = make_response()
    # 请求百度url并取得响应内容
    r = requests.get('http://www.baidu.com')
    # 如要还原请求的headers
    response.headers.update(r.headers)
    # 输出请求百度得到的数据
    response.data = r.text
    
    return response

Answer 5

import urllib2

response = urllib2.urlopen("http://www.baidu.com")  # 传入一个URL，协议是HTTP协议
print response.read()  # response对象有一个read方法，可以返回获取到的网页内容。

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