android - Activity之间传递Map<String,Object>

Question

listview.setOnItemClickListener(new OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> parent, View view,
                int position, long id) {
            Intent it = new Intent(getActivity(), ReleaseDetail.class);
            final SerializableMap myMap = new SerializableMap();
            myMap.setMap(tempList);// 将map数据添加到封装的myMap中
            Bundle bundle = new Bundle();
            bundle.putSerializable("map1", myMap);
            it.putExtras(bundle);
            startActivity(it);
            getActivity().finish();
        }
    });

public class SerializableMap implements Serializable {

private static final long serialVersionUID = 3958588986554810147L;
private Map<String, ReleaseContents> map;

public Map<String, ReleaseContents> getMap() {
    return map;
}

public void setMap(Map<String, ReleaseContents> tempMap) {
    this.map = tempMap;
}

}

ReleaseContents是一个实体类也实现了Serializable 接口还是报以下错误呢！！！

07-12 12:51:58.093: E/AndroidRuntime(12270): java.lang.RuntimeException: Parcelable encountered IOException writing serializable object (name = XXX.SerializableMap)XXX
查资料说是对象也是要先序列化接口，我ReleaseContents都实现了的呀！请问是哪里错了哦！

Answer 1

The classes used under the ReleaseContents class also need to implement the Serializable interface. For example, your ReleaseContents class has an attribute that is Version< /code> class, then this Version class may implement the Serializable interface. ReleaseContents类下使用到的类也需要实现Serializable接口，例如你的ReleaseContents类里面有个属性是Version类，那么这个Version类也许实现Serializable接口。

回到你的例子，很明显，在ReleaseContents类有个属性是Bitmap类，Bitmap并没有实现Serializable接口，而是实现了Parcelable

Back to your example, it is obvious that the ReleaseContents class has an attribute of the Bitmap class, and Bitmap does not implement Serializable< /code>interface, but implements the Parcelable interface. 🎜

Answer 2

Use Android's serialization class instead of the traditional java serialization class
Parcelable this. Or use the Gson tool to convert the map into a String, then pass it and parse it into a map

Answer 3

map没有实现序列化的接口，无法实现序列化，可以尝试一下hashmap，hashmap原本就可以保存在bundle中，也可像楼上一样使用parcelableIt is also faster to achieve this.

Answer 4

Use a CacheUtil to save this map in memory