移动app - iOS app开发：如何解决拨打电话的特殊字符（如*和#）？用于呼叫转移

Question

普通的拨打电话如下：NSString *strForCallHZ = @"tel:10086";[[UIApplication sharedApplication] openURL:[NSURL URLWithString:strForCallHZ]]; 但是我要设置“取消呼叫转移”，需要拨打“##21#”。 第一次尝试：...

高洛峰 · Answer

NSURL *url = [NSURL URLWithString:@"tel:%23%2321%23"];

Try it?

大家讲道理 · Answer

I am also solving this problem now. Have you solved it?

移动app - iOS app开发：如何解决拨打电话的特殊字符（如*和#）？用于呼叫转移

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