javascript - nodejs express 中，throw 一个异常，如何指定响应号？

Question

throw new Error('asdasdad')

这样会返回
{

error: asdasdad,
error_code: 500,

}

如何指定error_code呢？

例如 throw new Error('asdasdad', 400)

Answer 1

Just write a class that inherits from Error. For example:

export default class ApiError extends Error {
  constructor(msg, code) {
    super(msg);
    this.msg = msg;
    this.code = code;
  }
}