bool isLine(int map[][4]) {
for (int i = 0; i < 4; i++) {
for (int j = 0; j < 4; j++) {
cout << map[i][j] << ' ' ;
}
cout<<endl;
}
if (map[3][0] * map[2][1]* map[1][2] * map[0][3] == 1) return 1;
//*
//*
//*执行到这行时报错,Signal: SIGSEGV (Segmentation fault)
//*
//*
if (map[0][0] * map[1][1] * map[2][2] * map[3][3] == 1) return 1;
for (int row = 0; row < 4; row++) {
if (map[row][0] *map[row][1]* map[row][2]* map[row][3] == 1) return 1;
}
for (int col = 0; col < 4; col++) {
if (map[0][col] * map[1][col]* map[2][col] * map[3][col]) return 1;
}
return 0;
}
如代码所示,求解
ringa_lee2017-04-17 15:38:42
It depends on the specific parameters passed in at the call point and how they are constructed. You have to post the calling code as well.
阿神2017-04-17 15:38:42
For a two-dimensional array, the first parameter does not need to be specified. The system can obtain the first-dimensional parameter based on the total size and the second-dimensional parameter specified when the array is initialized. This is a segfault. It should be the parameter you passed. There is a problem with the size of the parameter space. The space is too small, so that the one-dimensional parameter cannot reach 3.