C++ 如何替换Char*类型变量里的字符串？

Question

一个Char *类型的变量
如何替换它里面的某个字符串（如：Like）为空，或者删除该字符串？
遍历替换字符我知道该怎么做，但字符串呢？（不能遍历一个个的字符去替换，因为这个Char里也有可能包含了多个L，但我只需要替换Like里的L就行了）

Answer 1

First find out the positions of all pattern strings. After writing them down, you can strcpy them into a new string in sections.

Answer 2

Resolved:

char* del_char(char str[])
{
    int i = 0, j = 0;
    int ii=strlen(str)-strlen(strstr(str,"要删除的子串"));
    while(str[i] != 'rrreee')
    {
        if((ii <= i)&&(ii+X >= i)) //X代表要删除子串的长度-1
        {
            i++;
        }
        else
        {
            str[j++] = str[i++];
        }
    }
    str[j] = 'rrreee';
    return str;
}

Loop traversal, the efficiency is a bit low...

Answer 3

If your compiler supports C++11 regex, this replacement is easy to achieve using regular expressions and strings.