c++ lambda表达式的问题

Question

一个函数指针名称申明
typedef void* (*SFThreadFuncPtr)(void* pUser);
[](void* _This) -> void*｛｝
为什么这个lambda没办法传给这个SFThreadFuncPtr定义的变量？

Answer 1

[](void _This) -> void {}
[](void _This) -> void｛｝
编码～～

Answer 2

The type of

lambda expression is a closure and cannot be directly assigned to a pointer type. You can use std::function to wrap the lambda expression and then call it.

#include <functional>

std::function<void* (void*)> fun;

fun = [](void* _This) -> void* { return NULL;};

fun(NULL);