#-*-coding:utf-8-*-
from sys import exit
class newgame(object):
def __init__(self, start):
self.start = start
#self.cccl()
def play(self):
next = self.start
while True:
print "\n--------"
print next
room = getattr(self, next)
next = room()
def death(self):
print "this is death"
exit(-1)
def cccl(self):
print "this is bbbb"
#return self.al() 如果加上return 或者 exit 就成功不加则报错
#exit(1)
def al(self):
print "this is al"
action = raw_input("> ")
if action == '1':
return "death"
elif action == '2':
return "cccl"
ngame = newgame("al")
ngame.play()
line 17, in play
room = getattr(self, next)
TypeError: getattr(): attribute name must be string
请问这是为什么呢?
pyenv version
anaconda-2.0.1 (set by /usr/local/opt/pyenv/version)
但是放到 ideone.com 上就又不报错了
巴扎黑2017-04-17 14:54:41
getattr
The second parameter must be str
, and next = room()
in the code should be this. room
returns something other than str. Speaking of which, what the hell is room
? It doesn't appear at all in the code snippet.
PHP中文网2017-04-17 14:54:41
The correct way to write
is room = getattr(self, 'next')
.
You can think of getattr
as passing a text message named 'next'
to the object, requesting the content of 'next'
. Since it is a text message, it must be a string.