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c++ - read-only variable is not assignable问题

不知道该如何叙述这个问题,请看代码:

#include <set>
#include <iostream>
using namespace std;

struct test {
    int data[3];
};

int main(void) {
    test t1;
    set<test> s;
    s.insert(t1);
    s.begin()->data[0] = 1;//此处赋值报错:read-only variable is not assignable

    return 0;
}

应该是set内部的问题吧?
求高人解释,非常感谢...

PHP中文网PHP中文网2764 days ago869

reply all(3)I'll reply

  • 高洛峰

    高洛峰2017-04-17 14:27:34

    The elements in the set cannot be changed, they can only be added or deleted. http://www.cplusplus.com/refe...

    Sets are containers that store unique elements following a specific order.
    
    In a set, the value of an element also identifies it (the value is itself the key, of type T), and each value must be unique. The value of the elements in a set cannot be modified once in the container (the elements are always const), but they can be inserted or removed from the container.
    
    Internally, the elements in a set are always sorted following a specific strict weak ordering criterion indicated by its internal comparison object (of type Compare).
    
    set containers are generally slower than unordered_set containers to access inpidual elements by their key, but they allow the direct iteration on subsets based on their order.
    
    Sets are typically implemented as binary search trees.

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  • ringa_lee

    ringa_lee2017-04-17 14:27:34

    It seems to mean: Read-only variables cannot be assigned. . .

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  • PHP中文网

    PHP中文网2017-04-17 14:27:34

    The iterator of set is read-only and does not allow modification (because the elements are sorted internally in set, changing the value of the elements at will may destroy its ordering);

    To change the value of an element, you can only delete the old one first and then insert the new one

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