ifstream input("D:\\trans.txt");
ifstream input;
inout.open("D:\\trans.txt",ifstream::in);
wchar_t const name[] = L"D:\\trans.txt";
ifstream input(name);
上面的几种方法都试了,还在exe文件右键以管理员身份运行了,但还是打不开文件。
网上也没找到解决方法。请问要怎么办。谢谢。
PHPz2017-04-17 14:26:04
What is the specific error? I wrote it myself and tried it. It can be opened. You can copy it and try it. Could it be that I forgot to read from the file, or did I use cin to read?
#include <fstream>
#include <iostream>
#include <string>
using namespace std;
int main()
{
ifstream in("D:\zz.txt");
string res;
while (getline(in, res))
{
cout << res << endl;
}
return 0;
}
Let’s try this one below. . . , directly read the characters into the file, and then open it, and see if it can be opened successfully? I can try it, can you try it? . . .
#include <fstream>
#include <iostream>
#include <string>
using namespace std;
int main()
{
ofstream ou("D:\zz.txt");
string test("hello world");
ou << test << endl;
ifstream in("D:\zz.txt");
if (in.is_open())
{
cout << "opened!\n";
}
string res;
while (getline(in, res))
{
cout << res << endl;
}
return 0;
}